Determining OS and Processor Problem!

[Joye]

I made a small project which is a part of a bigger one, this project is a form of one button with two textboxes.

This code works when user clicks on the button:

Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
        If System.Environment.Is64BitOperatingSystem = True Then
            TextBox1.Text = "64-bit Operating System"
        Else
            TextBox1.Text = "32-bit Operating System"

        End If

        If System.Environment.Is64BitProcess = True Then
            TextBox2.Text = "64-bit processor"
        Else
            TextBox2.Text = "32-bit processor"
        End If
    End Sub

With that code I wanted to tell the user (or the bigger project) what operating system and type of processor he has on his PC?

I tried the program on many devices and was fine until one day it showed me a x64 Operating System on a 32-bit Processor, and I know it's impossible.

So I knew that there is a problem with determining the right Processor.

I need to correct this code to determine and tell the exact OS and Processor type.

Thank you

[PlausiblyDamp]

System.Environment.Is64BitProcess isn't telling you if the processor is 32 or 64 bit just if the current Process is. Then again if they are running on anything made in the last 10 years or so it will probably be 64bit anyway as Intel haven't made 32bit desktop cpus for over ten years and I imagine AMD are the same.

[Joye]

System.Environment.Is64BitProcess isn't telling you if the processor is 32 or 64 bit just if the current Process is.

Then what tells?

Then again if they are running on anything made in the last 10 years or so it will probably be 64bit anyway as Intel haven't made 32bit desktop cpus for over ten years and I imagine AMD are the same.

I know but I have targeted users with Xp too

[PlausiblyDamp]

Is there a reason you need to know the CPU architecture if you know the OS architecture?

The easiest way I can think of might be to check the environment variable PROCESSOR_ARCHITECTURE using https://docs.microsoft.com/en-us/dot...ramework-4.7.2 and see what it says, on my laptop it reports AMD64 so it is a 64 bit architecture.

[Joye]

Is there a reason you need to know the CPU architecture if you know the OS architecture?

The easiest way I can think of might be to check the environment variable PROCESSOR_ARCHITECTURE using https://docs.microsoft.com/en-us/dot...ramework-4.7.2 and see what it says, on my laptop it reports AMD64 so it is a 64 bit architecture.

The reason is I want to determine what Active solution I should use with the user like If i should use:
x86?
x64?
Any CPU (prefer 32 Checked)?
Any CPU (prefer 32 Unchecked)?

and then know what Microsoft.ACE.OLEDB.12.0' provider should be installed?

[ident]

The code posted is correct. Only thing I can thinkof was a VM in play but then still....

[PlausiblyDamp]

The reason is I want to determine what Active solution I should use with the user like If i should use:
x86?
x64?
Any CPU (prefer 32 Checked)?
Any CPU (prefer 32 Unchecked)?

and then know what Microsoft.ACE.OLEDB.12.0' provider should be installed?

Unless you really need to run as a 64 bit process then you could go for AnyCPU prefer 32 bit. That way you will run as a 32 bit process on a 32 bit OS or a 64 bit OS that has support for 32 bit code. The only time it will run as a 64 bit process is if you are running on a 64bit OS that doesn't support 32 bit code (which is pretty unusual for a desktop these days anyway).

The actual CPU shouldn't really make a difference, in fact neither should the OS - just check the value of System.Environment.Is64BitProcess to discover if you are running as 32bit or 64bit and act accordingly.

[ident]

Environment.Is64BitOperatingSystem does exactly what you ask.

[Joye]

Environment.Is64BitOperatingSystem does exactly what you ask.

Then what Exactly I need??

[Joye]

Environment.Is64BitOperatingSystem does exactly what you ask.

Then what Exactly I need??

[ident]

Please everyone stop editing posts, its getting confusing replying. lol