# Thread: Calculating Decibels of a server

1. ## Calculating Decibels of a server

Hi,

Could someone please calculate the decibels of a computer server given the following:

Voltage: 0.6V
Power usage: 1KW

Tried using an online calculator but it gives a different result depending on what parameter I enter.

Thanks,

Nightwalker83  Reply With Quote

2. ## Re: Calculating Decibels of a server

I have taken the non-math approach an download the "Sound Meter" app for Android.  Reply With Quote

3. ## Re: Calculating Decibels of a server Originally Posted by Nightwalker83 Hi,

Could someone please calculate the decibels of a computer server given the following:

Voltage: 0.6V
Power usage: 1KW

Tried using an online calculator but it gives a different result depending on what parameter I enter.

Thanks,

Nightwalker83
The decibel calculation is done using a ratio of 2 values which are normally 2 power values (i.e. powerOut/powerIn). I'm not sure it make sense to calculate the decibels of 0.6V and 1KW. Now if you had the current consumption at 0.6V, you could then get the decibels using
dB = 10* LOG ((0.6V * I)/1KW)  Reply With Quote

4. ## Re: Calculating Decibels of a server

The consumption for the whole unit is 1000w if that helps?

Edit:

I tried to calculate the decibels using an online calculator and it came out at 30Db or -4.4V. However, when I used the app mentioned in post #2 the Db came out as between 70Db and 90Db which, I am told is what it should be. I think the calculators were only doing the calculation for one fan whereas this server has three fans.  Reply With Quote

5. ## Re: Calculating Decibels of a server

I could use a little context for this. Normally decibels are in reference to sound pressure, but not always. pH calculations use the same equation (10*LOG(ratio of Hydronium ions)). In your case, you have mentioned voltage and watts, and sound so I'm not sure what you are trying to figure out. I can say that dB's are calculated by taking the LOG of some ratio. It needs to be a ratio because the LOG works on a unitless number. So I'm not sure it makes sense to say LOG(x Volts) or LOG(x Volts/y Watts). It does make sense to say LOG(x Volts/y Volts).
So if you explain a bit more about what you are trying to do and where your number are coming from it would help.
kevin  Reply With Quote

6. ## Re: Calculating Decibels of a server

Yeah, I would have thought that Db was calculated using wattage. Although, seeing as I am not really familiar with it I just included the other values such as it mention on the calculators.

I am trying to confirm the number of decibels given by the server as picked up by the app mentioned in post #2 to make sure the calculations are correct. I am thinking of soundproofing the server I am trying to calculate the Dbs of.  Reply With Quote

#### Posting Permissions

• You may not post new threads
• You may not post replies
• You may not post attachments
• You may not edit your posts
•