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Type: Posts; User: geekmaro

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  1. Re: Vb6: check if textbox is free from more than one specific word

    you were right actually your code was much better and simple it worked well
    If InStr(Text1.Text, "demo") or InStr(Text1.Text, "test") or InStr(Text1.Text, "trial") then MsgBox "not free!"
  2. Re: Vb6: check if textbox is free from more than one specific word

    works!
    thax a lot u always help me out!
  3. Re: Vb6: check if textbox is free from more than one specific word

    else i dont wana use
    plz give me code for my goal
    im noob
    i searched google but nothing found
    helpppp
  4. Re: Vb6: check if textbox is free from more than one specific word

    i need to display msgbox when those 3 words do not exist
    i dont wana use "and" / "or"
    i need something more complicated than that
    plz help
    i need to put all words together into (demo+test+trial )...
  5. [RESOLVED] Vb6: check if textbox is free from more than one specific word

    how to check if textbox is free from more than one specific word
    for example" if text1 does not contain these words (demo test trial)

    i have this code but i dont wana use it, i dont wana use...
  6. [RESOLVED] vb6; parsing text to list listbox

    i solved it my self
    in case anyone need this here is code:

    List1.Clear
    Dim sInput As String
    sInput = Text1.Text
    Dim Item
    For Each Item In Split(sInput, "</option>")
    Item =...
  7. Replies
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    2,222

    Re: [RESOLVED] VB6: listbox run-time error 380

    oh this guy again.. simply a hater
    im working on database filtering program
    plz dont even open my posts again!
  8. Replies
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    2,222

    Re: VB6: listbox run-time error 380

    hey friend
    your code is too complicated
    look how i made it very simple:

    If List1.ListIndex = List1.ListCount - 1 = False Then
    List1.ListIndex = List1.ListIndex + 1
    Text2.Text =...
  9. Replies
    11
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    2,222

    Re: VB6: listbox run-time error 380

    let me try to explain
    i want to move to each item one by one, select it and move on to next item from A to C
    when it reaches C i get error when i try to move to next item because it is last item...
  10. Replies
    11
    Views
    2,222

    Re: VB6: listbox run-time error 380

    well this is how i solved it:

    If List1.ListIndex = List1.ListCount - 1 = False Then
    List1.ListIndex = List1.ListIndex + 1
    Text2.Text = List1.List(List1.ListIndex)
    End If

    which means if...
  11. Replies
    11
    Views
    2,222

    [RESOLVED] VB6: listbox run-time error 380

    I have a listbox with items like this:
    A
    b
    c
    i want to select and display each item in textbox, but when it reaches end i am getting error: run time error 380 invalid property value
    here my...
  12. Replies
    6
    Views
    1,377

    Re: VB6: get text between

    Worked like a charm!
    thank you very much
  13. Replies
    6
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    1,377

    Re: VB6: get text between

    i did but i couldnt find anything, what i searched for was very specific
  14. Replies
    6
    Views
    1,377

    Re: VB6: get text between

    it is html and i cannot publish it here because it require login to acccount
    so plz help me with text i provided you
  15. Replies
    6
    Views
    1,377

    [RESOLVED] VB6: get text between

    dellll
  16. Re: [RESOLVED] VB6: parsing all values to listbox

    worked!!
    thank u so much
  17. Re: [RESOLVED] VB6: parsing all values to listbox

    no i dont, i am noob
    plz give me working code
    thanx
  18. Re: [RESOLVED] VB6: parsing all values to listbox

    not working :(
    plz give me full code
    thx
  19. Re: [RESOLVED] VB6: parsing all values to listbox

    Option Explicit

    Private Sub Form_Load()
    Dim sInput As String
    Dim lPos1 As Long, lPos2 As Long
    Dim sValue As String
    Dim bStartAdding As Boolean

    sInput = "class='input1'><option...
  20. Re: [RESOLVED] VB6: parsing all values to listbox

    i didnt understand where to put that, plz can you u give me full code
    thx
  21. Re: [RESOLVED] VB6: parsing all values to listbox

    i have all this text in text1.text

    align="right">City:</TD><TD align="left" colspan="2"><INPUT class="input1" name="txtCity" type="text" value=""></TD><TD>&nbsp;&nbsp;&nbsp;</TD><TD...
  22. Re: [RESOLVED] VB6: parsing all values to listbox

    error! object required: If sValue = txtCountry.Text Then bStartAdding = True

    i changed that line to: If sValue = "txtCountry" Then bStartAdding = True
    but nothing happen it does not work
    help...
  23. Re: [RESOLVED] VB6: parsing all values to listbox

    i need to get name of countries only to listbox, the countries start from (txtCountry to submit), so from (Albani to Vietna)


    align="right">City:</TD><TD align="left" colspan="2"><INPUT...
  24. Re: VB6: parsing all values to listbox

    worked 10/10
    thank you!
  25. [RESOLVED] VB6: parsing all values to listbox

    I have this text and i need to get all countries inside value=""> to list box, plz help i searched everywhere but i cannot find anything

    " class="input1"><option value=""></option><option...
  26. Replies
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    1,003

    Re: VB6: filter text

    got it thanx for the tip
    text1.text = "["4719 Ericka Course, Suite 525, 31545, Lake Celestine, New Jersey, United States"]"
    Dim temp As Variant
    Dim str As String
    str = Text1.Text
    temp =...
  27. Replies
    3
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    1,003

    Re: VB6: filter text

    thanx
  28. Replies
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    1,003

    [RESOLVED] VB6: filter text

    i need to get text from this to text1 and text2 and text3 and text4

    ["4719 Ericka Course, Suite 525, 31545, Lake Celestine, New Jersey, United States"]

    text1= 4719 Ericka Course
    text2= 31545...
  29. Re: [RESOLVED] Vb6: Delete first line of multiline textbox

    @dilettante
    i got it working, thanx so much
    here ur code modified:

    Private Const WM_GETTEXTLENGTH As Long = &HE&
    Private Const EM_LINELENGTH As Long = &HC1&
    Private Declare Function...
  30. Re: [RESOLVED] Vb6: Delete first line of multiline textbox

    No i want delete only first line
    ur code freezes i click on textbox and try to delete again
  31. Re: [RESOLVED] Vb6: Delete first line of multiline textbox

    this code works only when u have more than 1 line
    when i tried with just one line it does not work
  32. Re: [RESOLVED] Vb6: Delete first line of multiline textbox

    omg my code does not work with more than 1000 lines :(
    i tried ur code it didnt work
    did u try it with multiline textbox ?
    plz help
  33. Re: Vb6: Delete first line of multiline textbox

    if i type something and i try ur code, it does not work
    here how i solved it:

    Private Sub Command1_Click()
    DeleteLine Text1, 1
    Dim n As Long
    Dim arr() As String
    arr() = Split(Text1.Text,...
  34. [RESOLVED] Vb6: Delete first line of multiline textbox

    i wana delete first line from multi line textbox
    i used this code: Text1.Text = Mid(Text1.Text, InStr(Text1, vbCrLf) + 2)
    but it does not work when i write 1 line and keep mouse pointer on same...
  35. Re: VB6 chromium,Chrome core only one dll

    i have a problem
    i copied your code and tested it
    but it does not validate the input
    i had to click on button to fill form, wait for form the show error: fields not filled, and then i click button...
  36. Re: VB6 chromium,Chrome core only one dll

    i told him in pm, if browser work i will pay you
  37. Re: VB6 chromium,Chrome core only one dll

    i will pay when u show me how to fill form
    i dont need just go url, i need to fill form and click buttons
  38. Re: VB6 chromium,Chrome core only one dll

    how to get fill a form inside your browser?
    i tried:
    SBrowser1.Document.GetElementById("userName").Value = "user123"
    SBrowser1.Document.GetElementById("continue").Click
    but it does not work
  39. Re: VB6 chromium,Chrome core only one dll

    i cant run it, everything in Chinese
    even i changed files names from Chinese to English but failed
    anyone can send English copy here in archive?
  40. Re: [RESOLVED] Vb6: elapsed time + time in label1.caption (new problem)

    i got it
    mStartTime = Now
    that simple
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