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-1 :bigyello:
Quiz question: would that be a horizontal or vertical asymptote?
Horizontal of course, only wouldn't 0 be the correct answer in that case? Yep. :thumb:
Infinite...do I win now?
Good. Now what is the second antiderivative of 9.8?
This should be easy. It since 9.8 is the acceleration due to gravity.
4.9x2+Cx+C
Cats will never approach infinity.Quote:
Originally Posted by eyeRmonkey
Cause God kills too many kittens.
Dogs will rule the earth as they will approach infinity because they are, well, dogs. :D
And Schroedinger has the rest.Quote:
Originally Posted by capsulecorpjx
Very good. :)Quote:
Originally Posted by timeshifter
How long ago did you take calc?
You know what the sad part is? We havn't even learned about integrals yet. I actually read ahead in the book. I'm pathetic, I know. :)
started my junior year in high school.. that's almost two years ago...
twelvty
?? Calc? last time I was in calc was 2 days ago..
Start > Run > Calc.exe
;)
Warning, this is also the same as schfifty five ;)Quote:
Originally Posted by wossname
This thread has really made my day.
shwam? doo? doo and heif? sheven? shfor-teen-teen?Quote:
Originally Posted by thegreatone
...
schfifty five?
isn't anti derivitive = integrate then it shoudl only be f(x) = 9.8x + c
second antiderivative... so take the integral of what you have.
Timeshifter is correct. (As always ;))
Me and my friend were teaching ourselves integration today and we couldn't figure out how to do the integral of 2 polynomials divided by each other (we couldnt find it in the book):
2x²+9
5+x+x3
Someone want to walk me through that? hehe.
Damn... i should really read stuff more carefully :blush: , makes me think how badly i must of stuffed up my last exams
Quick tips:
If the top is the derivative of the bottom then its log to the base e of the bottom:
2x+9
x²+9x+3
= ln(x²+9x+3) + c
if the top is of a higher degree than the bottom, then you'll need to do long devision, then integrate it. Also try finding out a way to simplify the equation before integrating.
OMG, stop reminding me of school :eek:
I've been trying very hard to forget it all.
By long division do you mean synthetic division?Quote:
Originally Posted by Andrew G
When reading ahead in the book, I saw a bunch of stuff on log and ln, but I didn't get a chance to see when and where you used it. It did mention that you had to use it when the exponenet was -1 though.
No... urgh... hang on I'll dig up my old maths books that I've been meaning to throw out :D
What are you doing in school at this time of the year :confused:
∫(1/x) = ln|x| + c
so it follows that
∫(ax/bx)
= ∫[ax*(1/bx)]
... eh... work it out yourself :D
Hiesenberg isn't certain about that, you know.Quote:
And Schroedinger has the rest
ASM > Maths
asm == maths
mostly
I wish I was out of school this early. Winter break doesn't start for another 2 weeks.Quote:
Originally Posted by penagate
Even if I was out of school, I would still be reading my calc book. I am just nerdy like that... Well, maybe I wouldn't be learning calc during winter break, but thats only because I would be programming. :)
speakin of programmin.. I think i'm gonna start work on another fairly big project... nothing compared to MSP, but still big nonetheless... and i was wondering if anyone wanted to help me in creating the plot, items, locations, blah blah blah behind the game...
but when you use the power rule thingy:Quote:
Originally Posted by penagate
∫[xn]Then
= (xn+1)/(n+1)
∫[ax*(1/bx)]That makes n=-1 in this case and n+1 = 0 so that part would go away... right? Thats the part that was confusing me before. Or am I missing something involving log or ln?
= ∫[ax*(bx)-1]
So it will be a game? Aren't you still missing your VB6 DLLs?Quote:
Originally Posted by timeshifter
Quote:
Originally Posted by eyeRmonkey
I've got the runtimes, so I have no problems programming as long as there arent many components or references used... I do have the RichTextBox component, and that's really all I need for what I'm doing.
Okay... sounds good. What are you doing then? A game? Thats what it sounded like.
yeah. Kinda like a Mud game without the multiplayer part.. just a large, text based, single player adventure.. with a rep system to make things interesting...
It's gonna be almost pure code.. hell, the GUI is already done.. just a rich text box, text box, frame, and a few labels.. all the rest is code..
damn this is gonna take a long time..,
Ya know what? I'm just gonna start a thread in the Project Comm area... if you want to help with design (that's all i'm doing right now), then just pop in and check it out. All ideas welcome, most serious ones will likely be used!
Sounds good. I'll check it out.
So back to integration. Does anyone have any insight into my question in post #32?
Can't help with that, but as for the thread title?
The limit as cats approaches infinity is...
42
I demand a strict mathmatical proof of how you came to that conclusion!
:D
The answer is 8.
You turn the infinity sign veritical then it becomes 8 :D
Tricky. :)
Hint, hint.... RobDog888. I'm triple infinity. :D
ax * 1/bx = a/b since x crosses out hence the answer isQuote:
Originally Posted by eyeRmonkey
(a/b)x + c
and lim cats → ∞ is 3.1415926535897932384626433832795
I didn't intend that :blush:
I meant,
∫[(ax+c)/(bx+d)]
which according to your integrator link is
[(ax+c)x]/(bx+d)
I'm out of school forever :DQuote:
Originally Posted by eyeRmonkey
I think the integrator is stuffed, it doesn't seem to recognise the x hence it calculates thinking that everything is a number.
Heres an example
*Image Removed*
Whoa!
Andrew, you lost me on the second step. Why are there 2 terms all of the sudden? Where did 15/2 come from?
I'll stare at it some more later. Maybe I'll come up with something.
The top is the same as it was before - that's algebra for you.
3/2 * (2x+1) + (15/2) = 3x + 3/2 + 15/2 = 3x + 18/2 = 3x+9.
Which is what you had originally.
Okay I see it now, and I figured it was something like that. I am just curious how you separated it out like that. I mean I see how. But why? Is there a pattern to the madness or is it just something you figure out after working with intergrals for a while?
I guess the point was to get (2x+1)/(2x+1)? But I never would have figured out which fractions to factor out.
Thanks for the help guys.
If anyone is interested, I took my calculus final today. I got a 94%. :)
good job. now get programming.
Congratulations :)
As for why i split them up, you'll notice that one of the fractions becomes 1 and the other is simple to integrate, hence by spliting a hard integral into 2, 3 or even more easier integrals, you are able to get the answer easier.
Okay. I just never would have picked those fractions. I see it now, but I never would have thought of it. I was hoping there was some rule or rule-of-thumb that helped. I guess I will just have to get used to it. :)
The only problem I missed on the calc final was about maximizing the area of 2 adjecent pig pens with only 18 feet of fencing. I don't even know what I did wrong, but I will check it on Monday (we don't have school on Friday because today was the last day of finals).
Reminds me of maths when i was still as school (1 month ago) ... Oh to pick the fractions, make the first fraction the same as the bottom (only if top degree = bottom degree, like example) then add any extras to make sure you don't change the question, like i added the 3/2. Its really just rearranging the integral to something simplier without modifying the actual question.Quote:
Originally Posted by eyeRmonkey