There is a recurring number.
Sam: I disagree with your proof. Note the following.
Recurring .9999 is a shorthand notational representation of the sum of a series, namely the following.
DecimalSeries(N) = 9/10 + 9/100 + 9/1000 + 9/10000 + . . . + 9/10^N
Consider the following series, which corresponds to recurring .FFFFF in hex notation.
HexSeries(N) = 15/16 + 15/256 + 15/4095 + 15/65536 + . . . + 15/16^N
I have coined the notation DecimalSeries(N) & HexSeries(N) to represent the sum of the first N terms of the respective series.
For all N, DecimalSeries(N) < Hexseries(N) < 1
QED: there is a real number greater than recurring .9999 and less than one.
a point doesn't have a size
Quote:
Originally posted by CiberTHuG
Sam, if you can double it, then it isn't infinity. But to ask yourself the same question, if I doubled Life Universe and Everything, what do I get? If I was able to double it, did I really have everything?
If you had a point in space, can you halve it? If so, did you really have a singular point?
Infinity and Infinitesimal exist. You can't represent them with any number. That leads to the underflow problem that makes people think that 0.999... is equal to 1.
also everything is being defined by human, oh yeah and if you want to apply something on reality, go find it first. Good explanation fox :)