[RESOLVED] How many"k" are in my textboxes

How many"k" are in my textboxes?
I want help for the code that will check a collection of 10 textboxes how many letters"k"are in my textboxes and to see the number in a label1
thank you

vb.net Code:

Dim CharCounter As Integer = 0
For Each txtbox As TextBox In Me.Controls.OfType(Of TextBox)()
    Dim c = Aggregate chars In txtbox.Text Where chars = "k"c Into Count()
    CharCounter += c
Next
MsgBox("Total number of character k in all textboxes is:" + CharCounter.ToString)

That code will only work on .NET 3.5 wont it though cicatrix?

An alternative that will work in .NET 2.0 would be something like:

vb.net Code:

Dim CharCounter As Integer = 0
For Each txtbox As TextBox In Me.Controls.OfType(Of TextBox)()
    For Each letter As Char In txtbox.Text 
         If letter = "k"c Then
             CharCounter += c
         End If
     Next
Next
MessageBox.Show("Total number of character k in all textboxes is:" + CharCounter.ToString)

Yes, my code is for .NET 3.5. I really don't see any reason to continue developing for .NET 2.0 after a newer version is available (and it's free).
LinQ helps enormously and I can't imagine how I managed without it. Still, it's a little more than 'syntactic sugar' but it allows to focus on the main things, not the peculiarities of implementation.

Quote:

---

Originally Posted by cicatrix

Yes, my code is for .NET 3.5. I really don't see any reason to continue developing for .NET 2.0 after a newer version is available (and it's free).

---

That is a little naive... a lot of people either have an existing program that is using .NET 2.0 that they have to support or they simply dont want to force their users to have to download and install the rather large 3.5 framework (plus SP1) package. A lot more people have .NET 2.0 installed (every Vista user for example as it comes pre-installed) than people have .NET 3.5 installed. I'm sure there are other reasons but those are the first things I think of - after all if there was no reason then every .NET developer would be using 3.5... and that clearly isn't the case.

With memas's here I'm sure he's got vs2008 or 2010 :) Your points are valid and well taken though.

Yeah I'm sure in this particular case using LINQ wont be a problem at all, I just thought it worth mentioning that it requires 3.5 in case the OP was not aware :)

cicatrix
how can i will put the collection of mytextboxes? i dont want all the textboxes

Well, either you should have some criteria or use your custom collection:

vb.net Code:

Dim myCol As New List(Of TextBox)
 
myCol.Add(Textbox1)
myCol.Add(Textbox5)

...
etc

the rest is the same:

vb.net Code:

Dim CharCounter As Integer = 0
For Each txtbox As TextBox In myCol
    For Each letter As Char In txtbox.Text 
         If letter = "k"c Then
             CharCounter += c
         End If
     Next
Next
MessageBox.Show("Total number of character k in all textboxes is:" + CharCounter.ToString)

P.S. If you use VS2003 or VS2005 you should use Chris's example.

cicatrix
1..if i have labels to take the k how will be the code for a group of labels ?

Quote:

---

Originally Posted by memas

cicatrix
1..if i have labels to take the k how will be the code for a group of labels ?

---

Guess what?

vb.net Code:

Dim myCol As New List(Of Label)

In all examples of this thread all it really takes is change TextBox with Label

There is a really hideous pun that can be made about this thread, but it may be American only, so I shall spare you all.

Quote:

---

Originally Posted by shaggy hiker

there is a really hideous pun that can be made about this thread, but it may be american only, so i shall spare you all.

---

do it

Excuse me, kind sirs, but what is 'a pun'? (I know I'm good with my English, but not that good, apparently).

cicatrix
is correct this code because the textbox says 2 and the k are 5
Private Sub Button72_Click_1(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
'HOW MANY K
Dim myCol As New List(Of Label)
myCol.Add(Label201)
myCol.Add(Label200)
myCol.Add(Label199)
myCol.Add(Label198)
myCol.Add(Label197)
myCol.Add(Label196)
myCol.Add(Label195)
myCol.Add(Label193)
myCol.Add(Label190)
myCol.Add(Label189)
myCol.Add(Label188)
myCol.Add(Label185)
myCol.Add(Label181)
myCol.Add(Label178)


Dim CharCounter As Integer = 0
For Each label As Label In Me.Controls.OfType(Of Label)()
Dim c = Aggregate chars In label.Text Where chars = "k"c Into Count()
CharCounter += c
Next
num34TextBox.Text = CharCounter.ToString

End Sub

Quote:

---

Originally Posted by memas

cicatrix
is correct this code because the textbox says 2 and the k are 5

---

This is because you're not paying attention to what people tell you.
If you use a custom collection then obviously you should iterate through it.

Here you iterate through ALL texboxes, you need to iterate only throught myCol.

Code:

---

Private Sub Button72_Click_1(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
        'HOW MANY K
        Dim myCol As New List(Of Label)
        myCol.Add(Label201)
        myCol.Add(Label200)
        myCol.Add(Label199)
        myCol.Add(Label198)
        myCol.Add(Label197)
        myCol.Add(Label196)
        myCol.Add(Label195)
        myCol.Add(Label193)
        myCol.Add(Label190)
        myCol.Add(Label189)
        myCol.Add(Label188)
        myCol.Add(Label185)
        myCol.Add(Label181)
        myCol.Add(Label178)


        Dim CharCounter As Integer = 0
        For Each label As Label In MyCol
            Dim c = Aggregate chars In label.Text Where chars = "k"c Into Count()
            CharCounter += c
        Next
        num34TextBox.Text = CharCounter.ToString

    End Sub

---

cicatrix the textbox always says 0 zero why?

Hmm, this should work.
Try renaming the label variable:

Code:

---

...
For Each lbl As Label In MyCol
    Dim c = Aggregate chars In lbl.Text Where chars = "k"c Into Count()
    CharCounter += c
Next
...

---

And it won't probably find 'K' (CAPITAL) - only 'k' (small)

the same thing zero

Quote:

---

Originally Posted by cicatrix

Excuse me, kind sirs, but what is 'a pun'? (I know I'm good with my English, but not that good, apparently).

---

Some people would call a pun the lowest form of humor, but it is actually just a play on words. For example, I should note that your code will find ALL the ks in a string, including the very rare case where two Ks come one after the other. This is very rare, and could be considered a special K because it refers to serial ks.

Now, in case it is not sold everywhere, Special K is a type of breakfast cereal.

shaggy hiker
why you dont try to help?

its sold here in the UK... and congrats on the terrible pun haha

Quote:

---

Originally Posted by memas

the same thing zero

---

Do these labels actually hold text containing small k English characters?

What is the text in your labels? Can you post some example?


P.S.
@Shaggy hiker: I may be not in a position to judge, but I too think it's a terrible pun :D

Quote:

---

Originally Posted by memas

shaggy hiker
why you dont try to help?

---

yeahhhh shaggy hiker, you're so unhelpful. Sometimes it makes me want to cry.

cicatrix is working the mistake is mine thank you

Quote:

---

Originally Posted by memas

shaggy hiker
why you dont try to help?

---

Sorry, I don't deal in LINQ, so as long as Cicatrix is going down that road and is approaching a solution to the problem, I have nothing to add.

However, I would suggest that doing something like this:

Code:

---

For Each label As Label In MyCol
    CharCounter += System.Text.RegularExpressions.Regex.Matches(label.Text,"[Kk]").Count
Next

---

would probably be faster. Haven't tested it, though, but it should match all K or k in the string and return the count of all such matches in the string.

Simpler (and without regex):

Code:

---

c = Aggregate chars In txtbox.Text Where (chars = "k"c Or chars = "K"c) Into Count()

---

Perhaps, but LINQ isn't fast, so I would question whether or not Regex isn't the faster solution.

Code:

---

    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click

        Dim myCol As New List(Of Label)
        For Each l As Label In myCol
            num34TextBox.Text = countK(l.Text, False).ToString
        Next

    End Sub

    Dim theCount As Integer = 0
    Private Function countK(ByVal inWhat As String, _
                            Optional ByVal CaseMatters As Boolean = True) As Integer

        theCount += inWhat.Count(Function(c) c = "k"c)
        If Not CaseMatters Then theCount += inWhat.Count(Function(c) c = "K"c)
        Return theCount

    End Function

---

CICATRIX
my mistake was that the k was with capital letter thats why i have problem now that i change the k in code with capital K is working perfect
thank you again

dbasnett
with this code i have errors

Quote:

---

Originally Posted by memas

dbasnett
with this code i have errors

---

My internet telepathy is down today, so if you could be more explicit in the details of your difficulty, perhaps I could help. Post the code.

relax for today tomorow i hope you are ok and i will ask you a difficult question
memas

Quote:

---

Originally Posted by Shaggy Hiker

Perhaps, but LINQ isn't fast, so I would question whether or not Regex isn't the faster solution.

---

Test it for yourself then. Regex was slower

Here's my results:
http://i48.tinypic.com/15g76dw.jpg

vb.net Code:

Imports System.Text.RegularExpressions
 
Public Class Form1
    Const MAX_ELEMENTS As Integer = 1000000
 
    Dim rng As New Random
    Dim btnLINQ, btnREGEX As Button
    Dim RefCount As Integer = 0 ' For reference purposes
    Dim TestArray() As String
    Dim TestList As List(Of String) ' To test Arrays vs Collections issue
 
 
    Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
        btnLINQ = New Button With {.Text = "Test LINQ", .Width = 200, .Height = 30, .Left = 10, .Top = 10}
        btnREGEX = New Button With {.Text = "Test REGEX", .Width = 200, .Height = 30, .Left = 10, .Top = btnLINQ.Bottom + 20}
        Me.ClientSize = New Size(btnLINQ.Right + 10, btnREGEX.Bottom + 10)
        Me.FormBorderStyle = Windows.Forms.FormBorderStyle.FixedDialog
        Me.Controls.AddRange(New Control() {btnLINQ, btnREGEX})
        Me.Text = "LINQ vs REGEX"
 
        PrepareTestObjects()
        AddHandler btnLINQ.Click, AddressOf TestLINQ
        AddHandler btnREGEX.Click, AddressOf TestREGEX
    End Sub
 
    Private Sub PrepareTestObjects()
        btnLINQ.Enabled = False
        btnREGEX.Enabled = False
        RefCount = 0
        TestList = New List(Of String)
        ReDim TestArray(MAX_ELEMENTS - 1)
        Dim x, c As Integer
        Randomize(Now.Ticks)
        For x = 0 To MAX_ELEMENTS - 1
            Dim l As Integer = rng.Next(10, 21) ' make a random length 
            Dim element As String = ""
            For c = 0 To l
                Dim randomChar As Char = Chr(rng.Next(33, 123)) ' random character from "!" to "z"
                element += randomChar
                If randomChar = "k"c Or randomChar = "K"c Then RefCount += 1 ' We'll know for sure how many k's here
            Next
            TestArray(x) = element
            TestList.Add(element)
        Next
        btnLINQ.Enabled = True
        btnREGEX.Enabled = True
    End Sub
 
    Private Sub TestLINQ(ByVal sender As Object, ByVal e As EventArgs)
 
        Dim KCount As Integer = 0
        Dim t As DateTime = Now
        For Each st In TestArray
            Dim Cnt = Aggregate chars In st Where (chars = "k"c Or chars = "K"c) Into Count()
            KCount += Cnt
        Next
        Dim ArrayTestDuration As TimeSpan = Now - t
 
        KCount = 0
        t = Now
        For Each st In TestList
            Dim Cnt = Aggregate chars In st Where (chars = "k"c Or chars = "K"c) Into Count()
            KCount += Cnt
        Next
        Dim ListTestDuration As TimeSpan = Now - t
 
        Dim ResultsStr As String = String.Format( _
        "Test on {4} elements of random strings using LINQ:{1}Test on array:{3}{0:mm:ss.FFF} ms {1}Test on list:{3}{2:mm:ss.FFF} ms{1}Found elements:{3}{5}{1}Reference elements:{3}{6}", _
        New Object() {ArrayTestDuration, Environment.NewLine, ListTestDuration, ControlChars.Tab, MAX_ELEMENTS, KCount, RefCount})
        MsgBox(ResultsStr, MsgBoxStyle.Information, "Test results for LINQ")
 
    End Sub
 
    Private Sub TestREGEX(ByVal sender As Object, ByVal e As EventArgs)
        Dim KCount As Integer = 0
        Dim t As DateTime = Now
        For Each st In TestArray
            KCount += Regex.Matches(st, "[Kk]").Count
        Next
        Dim ArrayTestDuration As TimeSpan = Now - t
        KCount = 0
        t = Now
        For Each st In TestList
            KCount += Regex.Matches(st, "[Kk]").Count
        Next
        Dim ListTestDuration As TimeSpan = Now - t
 
        Dim ResultsStr As String = String.Format( _
        "Test on {4} elements of random strings using REGEX:{1}Test on array:{3}{0:mm:ss.FFF} ms {1}Test on list:{3}{2:mm:ss.FFF} ms{1}Found elements:{3}{5}{1}Reference elements:{3}{6}", _
        New Object() {ArrayTestDuration, Environment.NewLine, ListTestDuration, ControlChars.Tab, MAX_ELEMENTS, KCount, RefCount})
        MsgBox(ResultsStr, MsgBoxStyle.Information, "Test results for REGEX")
 
    End Sub
End Class

So there I was, going to test the results, and my machine locked up. Numerous times I have tried to test regex and had this happen. Basically my code timer calls the init code once, and then each of the tests hundreds of thousands of times. I must be missing something.

Code:

---

    Dim testSTR As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
    Dim myCount As Integer = 0
    Private Function TestCase1() As Boolean 'One
        'Test One Code Follows
        myCount = Aggregate chars In testSTR Where (chars = "k"c Or chars = "K"c) Into Count()
        'End Test One Code
        Return True
    End Function
    '
    Private Function TestCase2() As Boolean 'Two
        'Test Two Code Follows
        myCount = System.Text.RegularExpressions.Regex.Matches(testSTR, "[Kk]").Count
        'End Test Two Code
        Return True
    End Function
    '
    Private Sub _init()
        'Code needed to get the Test to run.  NOT part of the timing.
        testSTR &= testSTR.ToLower
        testSTR &= testSTR
        'Only called once!!!
    End Sub

---

Yup, LINQ turns out to beat both Regex and the old fashioned looping through the characters. I have seen cases where LINQ was slower, but it is not in this case.

However, I haven't used LINQ much, nor have I used the type inference that is present in the LINQ example. When I copied that into my testapp, I found that type inference simply wasn't working in that app, despite using VS2008 targeting the 3.5 framework. Is there something else that I need to set?

Are you absolutely sure that the most optimized form of looping possible couldn't beat it? (Normally I would test it, but I have VS 2005.)

vb Code:

Dim i As Integer = 0, count As Integer = 0, kL As Char = "k", kU As Char = "K"
While i < str.Length
     If str.Chars(i) = kL OrElse str.Chars(i) = kU Then count += 1
     i += 1
End While

sort of thing? Or call ToCharArray() first? There are just too many different ways to use the simple loop.

Yeah, I tested that one, too. LINQ beat it handily. I didn't compare it directly to Regex, but they were in the same vicinity.

haven't read all the posts but:

vb Code:

MsgBox((From xItem In asd Where LCase(xItem) = "k").Count)

and actually linq is always faster ... except in cases where you need to evaluate the same thing multiple times... such as:

From xItem in asd where xItem.Somefunction() = "a" or xItem.Somefunction() = "b"

as Somefunction will be evaluated 2x where in a loop you could store this in a variable... of course u could do it like this:

From xItem In (From xItem In asd Select xItem, xItem.Somefunction) Where xItem.Somefunction = "a" Or xItem.Somefunction = "b" Select xItem.xItem

Thus only evaluating it in the inner linq query 1 time.