[RESOLVED] Clearing array is fast in VB5 but very slow in VB6

Quote:

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Originally Posted by DEXWERX

This could all be fixed if MS would Open Source VB.

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Not sure if Open Source is a good idea.
Think of the many different runtimes it could produce...
...on the other hand, I don't have a better idea.

I would prefer to get a new VB6+ from a company, at best MS.

Karl

Quote:

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Originally Posted by Karl77

Not sure if Open Source is a good idea.
Think of the many different runtimes it could produce...
...on the other hand, I don't have a better idea.

I would prefer to get a new VB6+ from a company, at best MS.

Karl

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right, cause then we would have the same mess as all the C++ and .NET developers. ;)
Despite my sarcasm - I'm not actually disagreeing.

If I were still using C++ primarily - I would go to great lengths to use the c runtime the OS uses.

Quote:

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Originally Posted by Elroy

Code:

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Option Explicit
'
Private Declare Function PerformCount Lib "kernel32" Alias "QueryPerformanceCounter" (lpPerformanceCount As Any) As Long
Private Declare Function PerformFreq Lib "kernel32" Alias "QueryPerformanceCounter" (lpPerformanceCount As Any) As Long
'

Private Sub Form_Load()
    Dim timeFreq As Currency
    Dim startTime As Currency
    Dim endTime As Currency
    Dim i As Long
    Dim a() As Variant

    PerformFreq timeFreq


    ReDim a(1 To 1000)
    For i = LBound(a) To UBound(a)
        Set a(i) = New Class1
    Next i
    '
    PerformCount startTime
    ReDim Preserve a(LBound(a) To LBound(a))
    PerformCount endTime
    MsgBox "Nanoseconds: " & Format$((endTime - startTime) / timeFreq * 1000000000, "0.000")



    ReDim a(1 To 1000)
    For i = LBound(a) To UBound(a)
        Set a(i) = New Class1
    Next i
    '
    PerformCount startTime
    For i = LBound(a) To UBound(a) - 1
      ReDim Preserve a(LBound(a) To UBound(a) - 1)
    Next
    PerformCount endTime
    MsgBox "Nanoseconds: " & Format$((endTime - startTime) / timeFreq * 1000000000, "0.000")



    ReDim a(1 To 1000)
    For i = LBound(a) To UBound(a)
        Set a(i) = New Class1
    Next i
    '
    PerformCount startTime
    Erase a
    ReDim a(1 To 1)
    Set a(1) = New Class1
    PerformCount endTime
    MsgBox "Nanoseconds: " & Format$((endTime - startTime) / timeFreq * 1000000000, "0.000")



    Unload Me
End Sub



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.....

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Just in case someone ends up here in search of high precision timestamps

ATTENTION!

The lines:

Quote:

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Private Declare Function PerformCount Lib "kernel32" Alias "QueryPerformanceCounter" (lpPerformanceCount As Any) As Long
Private Declare Function PerformFreq Lib "kernel32" Alias "QueryPerformanceCounter" (lpPerformanceCount As Any) As Long

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should be:

Quote:

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Private Declare Function PerformCount Lib "kernel32" Alias "QueryPerformanceCounter" (lpPerformanceCount As Any) As Long
Private Declare Function PerformFreq Lib "kernel32" Alias "QueryPerformanceFrequency" (lpPerformanceCount As Any) As Long

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Took me a while to see that!

And the timing resolution on my machine (W8.1) seems to be ~300 nanosecs, so it makes not much sense to display intervals smaller than that.

Another strange thing:
if you use LONG instead of CURRENCY, then the first call of PerformCount changes the value of the previously with PerformFreq assigned timeFreq

How on earth could this be ???

Thanks to Elroy for putting me on the right track and Happy New Year to all :cool:

Quote:

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Originally Posted by tubus

if you use LONG instead of CURRENCY, then the first call of PerformCount changes the value of the previously with PerformFreq assigned timeFreq

How on earth could this be ???

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Stack layout.

Local variables are allocated on the stack and Long variables are 4 bytes each while Currency variables are 8 bytes.

Passing the address of the first Long var to an API that outputs 8 bytes at this address effectively overwrites the second Long var.

cheers,
</wqw>

Quote:

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Originally Posted by wqweto

Stack layout.

Local variables are allocated on the stack and Long variables are 4 bytes each while Currency variables are 8 bytes.

Passing the address of the first Long var to an API that outputs 8 bytes at this address effectively overwrites the second Long var.

cheers,
</wqw>

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...aha, thanks!

Time to learn something new every day. :thumb:

For archive purposes and for anyone interested, here's a detailed explanation of what is going on: Faster VB6 / VBA class deallocation