And that your a moron!
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And that your a moron!
It's not my fault your brain cannot fanthom the infinitely small difference between .999 repeating and 1.
Anyone know of a fraction representing .999 repeating?
Infinity doesn't measure accuracy.
Absolute can.
Illiteracy is a big problem is this society.
Come on guys, can you see that Digitai is just jerking you? =).
The trick is to ignore until he posts something useful =).
Z.
1Quote:
Originally posted by DiGiTaIErRoR
Express .9 repeating as a real number.
:D
marnitzg knows what hes talking about!
Alright then, if 0.9(recurring) does NOT equal 1, explain this:
Given a positive real number x, find the positive square root of it (calling the positive square root Root(x)). Examining the behavior of Root(x) with different groups of values for x, it seems that:
If x > 1, x > Root(x) > 1
If x = 1, x = Root(x) = 1
If x < 1, x < Root(x) < 1
Let x = 0.9(recurring), the inequality must be satisfied:
0.9(recurring) < Root(x) < 1, so please do tell - exactly which real number (n) is between 0.9(recurring) and 1 such that n2 = 0.9(recurring)???
Quite a nice example of proof by contradiction.
Close enough.Quote:
Originally posted by marnitzg
1
:D
:rolleyes:
I will admit for any practical purpose .999... = 1.
But the truth is, it doesn't.
The difference is infininty small. But there is still a difference!
Express .999... as a fraction with result that will actually give you .999... no 1/1 stuff!
There would be nothing between .999... and 1.Quote:
Originally posted by A$$Bandit
Alright then, if 0.9(recurring) does NOT equal 1, explain this:
Given a positive real number x, find the positive square root of it (calling the positive square root Root(x)). Examining the behavior of Root(x) with different groups of values for x, it seems that:
If x > 1, x > Root(x) > 1
If x = 1, x = Root(x) = 1
If x < 1, x < Root(x) < 1
Let x = 0.9(recurring), the inequality must be satisfied:
0.9(recurring) < Root(x) < 1, so please do tell - exactly which real number (n) is between 0.9(recurring) and 1 such that n2 = 0.9(recurring)???
Quite a nice example of proof by contradiction.
Well, 1/9 = .111... and 8/9 = .888... then 1/9+8/9=9/9=1 but .111 and .888... = .999...
Inaccuracy of infinite.
I agree that our decimal system is incomplete in it's current form.
Hey Digital
you say
"The difference is infininty small."
and...
"Infinity doesn't measure accuracy"
I have the feeling those two contradict each other but oh well...
another thing you say is
0.8(recurring) + 0.1(recurring) = 0.9(recurring)
alright given this as a fact what can you say against this?
How can you argument against this?Code:1/3 = 0.333(recurring)
3/3 = 1
3*1/3= 3/3 = 0.333(recurring) + 0.333(recurring) + 0.333(recurring)
=0.990(recurring)=1
Well you can say that 1/3 is not 0.3(recurring), but you're gonna have to come up with some mathematical proof of it (i.e. not just saying "oh by the way infinite accuracy doesn't exist").
well I really can't discuss that with you to good here, since I took math in another language so my english math vocabulary is kind of limited... well for the 0.333...
isn't that proven?
I mean
1/3=0 remainder 1
so 10/3 = 3 remainder 1
shouldnt that be enough of a proof... I mean it shows that it't "perdiodic" right from the first step on... there can't be any change to that no matter how far you go....
it's not .990...Quote:
=0.990(recurring)=1
/\/\isanThr0p, You're otherwise incoherent.
You're dealing with infinity. Infinty - infinity is undefined. So you're trying to define a 'close' solution for an otherwise undefinable one. Since you cannot define infinity into the real number system. It's an idea, that's all, a concept, if you will.
9.999 infinite...
- .999 infinite
= 9.? undefined
haha
well following my argumentation that's really easy
10-1=9
well I get what you are saying... you are probably a really smart person I really don't want to offend you, but your argumentation is what you hear from highschool kids a lot...
I am really no big mathwiz so I wont go on about this... I stated what I think, I get what you are saying even though I think you are wrong...
math is a system of axioms and I believe what I stated is accepted as true, I can't say any more about it...
I am a highschool student. What does that prove? You can discriminate against me using my age?
My questions still remains. What do you add to .999... recuring to get 1?
.999... + 0 = 1
You could say .999... + .000... = 1, but an infinite number of recurring zero's is zero.
So, 1 - 0 = .999...
-Lou
The argument only gets more moronic.Quote:
Originally posted by NotLKH
.999... + 0 = 1
You could say .999... + .000... = 1, but an infinite number of recurring zero's is zero.
So, 1 - 0 = .999...
-Lou
I am in Highschool too (even though I am in 13th grade) and I am not going to discriminate against you because of your age...
You can't quantify infinite to a real number.
Stop trying.
In what Way?Quote:
Originally posted by DiGiTaIErRoR
The argument only gets more moronic.
:rolleyes:Quote:
Originally posted by NotLKH
In what Way?
Here's some consideration:
http://mathforum.org/library/drmath/view/55746.htmlQuote:
Ultimately, though, this probably won't _really_ make sense until you
come to grips with what it means for a decimal to repeat _forever_,
instead of just for a r-e-a-l-l-y l-o-n-g t-i-m-e.
When you think of 0.999... as being 'a little below 1', it's because
in your mind, you've stopped expanding it;
Great! an encore of nonsense.Quote:
Originally posted by nemaroller
Here's some consideration:
http://mathforum.org/library/drmath/view/55746.html
:rolleyes:
.999... only becomes 1 when you round.
Actually that makes sense DigitalError. You should actually read it.
I did read it.
And you think its nonsense?
Infinity is not accurate.
Unless you agree that:
If I give you Infinite dollar bills, and take back one, you have 999... repeating forever dollar bills.
:rolleyes:
Well, Mr. Error, I do have to admit that you've
got a great schtick to capture postcounts by living
up to your name by spouting disbelief against tried and true
mathematical concepts. And, BTW, your rolleyeye coment was
certainly well deserved, since I understood our simultanious
posts questioned and answered each other, and deserved no
furthur comment. But, I'm glad you did, it, along with the rest of
your comments.
:p
-Lou
You're trying to quantify infinity.
I do not need to explain why this is wrong.
1-.9=0.1
1-.99=0.01
1-.999=0.001
1-.9999=0.0001
well, DigitalError, if you can tell me when you stop writing all the 9s, I'll happily write a '1' on the end of my strings of 0s. Otherwise,
1-0.999...=0.000...=0
you are right, we can't quantify infinity. so an INFINITE NUMBER OF 9S simiply means the 9s are never ending. thus that means the 0s in 0.000... are never ending.
also, 0.999...=9/10+9/100+9/1000+...
do you know how to do the sum of an infinite geometric sequence? seeing how you are in high school and it is usually taught at gr. 11...
anywayz what does this equal to 9/10+9/100+9/1000+...
tell me (unless you want to argue first that there is no such thing is infinity and infinite sums like this one doesn't exists -- btw sin,cosine,pi,e all can be written as infinite sums in addition to other real numbers)!
However many 9s you can write after a decimal place you can always have enough 0's and a single 1 to add make it one.
.999... repeating forever does not truly exist. It's an idea. Like infinity is just an idea. There's nothing in the real world that has a measure of .999 repeating.
Like I said. In fantasy land, where your infinity can be a real number then you can have infinite repeating 9s.
But let me ask you this:
What's 111..., what's 999... no decimal place, just the number repeating forever. Infinity, right?
The same applies to .999 repeating. You're trying to manipulate infinity to a number. You can't do that.
so you are telling me that infinite sums and irrational numbers doesn't exist?
let me ask you, what is e? what is pi?
can you finish writing all decimal numbers of e and pi?
no! so i guess they are fantasy land numbers and they don't exist. right?
a little calculus knowledge since you probably haven't learnt that in high school (except for last year) yet. 0.999... converges infinitely close to 1. 999... converges to infinity. but we can't converge to infinity (or in your words, infinity can't be quantified). so 999... does not converge. we say that if it converges something, it is actually equal to something, thus the idea of limits.
if you can't agree to this, then you are denying the whole concept of limits and thus Calculus. well, you can refuse it now, wait till ur in university.
Wow.
Discrimination based on my age.
:rolleyes:
With such an attitude, its easy to see why you think it can't equal 1.Quote:
Originally posted by DiGiTaIErRoR
.999... repeating forever does not truly exist.
Unfortunately, just saying something doesn't exist doesn't make that statement true.
So, until you can prove such an hypothesis, I'd think its safe to say you are wrong.
And statements such as "You can't quantify infinite to a real number" certainly is not a proof, but merely another blind assertion.
"It's an idea".
Well, thats interesting. Everything is an Idea, a mental image of what is and what isn't.
Philosophically speaking, Nothing can be proven to truly exist, so your argument is pure philosophical drival.
All math is based upon concepts, and is purely a human invention.
There is no such thing as a number, they all are only conceptual in nature.
So, From your observation, .999... is as real as 1, since both are only ideas.
-Lou
this seems to be a nice way to dismiss my arguements! or do you plan to offer your opinion on how irrational numbers and calculus doesn't exist? i mean, i logically deduced these statements from your arguements!Quote:
Wow.
Discrimination based on my age.