SQL_lall
Actually, reading up a little on transfinite numbers, that is not the case.Quote:
aleph-0 + 1 = aleph-0
also: aleph-0 x 2 = aleph-0 (I think)
That's what happens with infinity
(aleph-0) + 1 = (aleph-0) + 1
AND
1 + (aleph-0) = (aleph-0)
Also
(aleph-0) x 2 = (aleph-0) x 2
AND
2 x (aleph-0) = (aleph-0)
What you are actually stating above is that (aleph-0) x 2 has the same cardinality as (aleph-0).
i.e. ====== =========
(aleph-0) =(aleph-0) x 2
