is it possible to get a pointer to point to an array and then pass that pointer into a function so the function can access the array and write into another array and then return the pointer to that array.
cheers
Peter
Printable View
is it possible to get a pointer to point to an array and then pass that pointer into a function so the function can access the array and write into another array and then return the pointer to that array.
cheers
Peter
Like that?Code:INT array1[10];
INT* pa1 = &array1[0];
INT* arrayfunc(INT* arr1, INT numitems)
{
INT* pa2 = new INT[20];
for(INT i = 0; i < numitems; i++)
{
//do whatever
}
return pa2;
}
INT main()
{
INT* arr = arrayFunc(pa1, 10);
}
Z.
I don't recommend you use new in a function without using delete on it, that can cause memory leaks or unexpected crashes.
If you're let's say trying to copy an array of fixed size to another of fixed size, pass a pointer to both arrays