Login failed.The login is from an untrusted domain and cannot be used..

Hello..

I have created a login form for my project,I have searched on google and found out to make the integrated security=false but it still doesnt work,and when i install it on another pc it shows me the error :

Code:

---

XCEPTION      : Handled
MESSAGE        : Login failed. The login is from an untrusted domain and cannot be used with Windows authentication.
SOURCE        : .Net SqlClient Data Provider
TARGETSITE    : Void .ctor(System.Data.ProviderBase.DbConnectionPoolIdentity, System.Data.SqlClient.SqlConnectionString, System.Data.SqlClient.SqlCredential, System.Object, System.String, System.Security.SecureString, Boolean, System.Data.SqlClient.SqlConnectionString, System.Data.SqlClient.SessionData, System.Data.ProviderBase.DbConnectionPool, System.String, Boolean, System.Data.SqlClient.SqlAuthenticationProviderManager)
STACKTRACE    :
  at System.Data.SqlClient.SqlInternalConnectionTds..ctor(DbConnectionPoolIdentity identity, SqlConnectionString connectionOptions, SqlCredential credential, Object providerInfo, String newPassword, SecureString newSecurePassword, Boolean redirectedUserInstance, SqlConnectionString userConnectionOptions, SessionData reconnectSessionData, DbConnectionPool pool, String accessToken, Boolean applyTransientFaultHandling, SqlAuthenticationProviderManager sqlAuthProviderManager)
  at System.Data.SqlClient.SqlConnectionFactory.CreateConnection(DbConnectionOptions options, DbConnectionPoolKey poolKey, Object poolGroupProviderInfo, DbConnectionPool pool, DbConnection owningConnection, DbConnectionOptions userOptions)
  at System.Data.ProviderBase.DbConnectionFactory.CreatePooledConnection(DbConnectionPool pool, DbConnection owningObject, DbConnectionOptions options, DbConnectionPoolKey poolKey, DbConnectionOptions userOptions)
  at System.Data.ProviderBase.DbConnectionPool.CreateObject(DbConnection owningObject, DbConnectionOptions userOptions, DbConnectionInternal oldConnection)
  at System.Data.ProviderBase.DbConnectionPool.UserCreateRequest(DbConnection owningObject, DbConnectionOptions userOptions, DbConnectionInternal oldConnection)
  at System.Data.ProviderBase.DbConnectionPool.TryGetConnection(DbConnection owningObject, UInt32 waitForMultipleObjectsTimeout, Boolean allowCreate, Boolean onlyOneCheckConnection, DbConnectionOptions userOptions, DbConnectionInternal& connection)
  at System.Data.ProviderBase.DbConnectionPool.TryGetConnection(DbConnection owningObject, TaskCompletionSource`1 retry, DbConnectionOptions userOptions, DbConnectionInternal& connection)
  at System.Data.ProviderBase.DbConnectionFactory.TryGetConnection(DbConnection owningConnection, TaskCompletionSource`1 retry, DbConnectionOptions userOptions, DbConnectionInternal oldConnection, DbConnectionInternal& connection)
  at System.Data.ProviderBase.DbConnectionInternal.TryOpenConnectionInternal(DbConnection outerConnection, DbConnectionFactory connectionFactory, TaskCompletionSource`1 retry, DbConnectionOptions userOptions)
  at System.Data.ProviderBase.DbConnectionClosed.TryOpenConnection(DbConnection outerConnection, DbConnectionFactory connectionFactory, TaskCompletionSource`1 retry, DbConnectionOptions userOptions)
  at System.Data.SqlClient.SqlConnection.TryOpenInner(TaskCompletionSource`1 retry)
  at System.Data.SqlClient.SqlConnection.TryOpen(TaskCompletionSource`1 retry)
  at System.Data.SqlClient.SqlConnection.Open()
  at System.Data.Common.DbDataAdapter.FillInternal(DataSet dataset, DataTable[] datatables, Int32 startRecord, Int32 maxRecords, String srcTable, IDbCommand command, CommandBehavior behavior)
  at System.Data.Common.DbDataAdapter.Fill(DataTable[] dataTables, Int32 startRecord, Int32 maxRecords, IDbCommand command, CommandBehavior behavior)
  at System.Data.Common.DbDataAdapter.Fill(DataTable dataTable)
  at DG.DentneD.LoginForm.button1_Click(Object sender, EventArgs e) in C:\Users\windows\Desktop\New folder (19)\dentned-master\DentneD\LoginForm.cs:line 56
  at System.Windows.Forms.Control.OnClick(EventArgs e)
  at System.Windows.Forms.Button.OnClick(EventArgs e)
  at System.Windows.Forms.Button.OnMouseUp(MouseEventArgs mevent)
  at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks)
  at System.Windows.Forms.Control.WndProc(Message& m)
  at System.Windows.Forms.ButtonBase.WndProc(Message& m)
  at System.Windows.Forms.Button.WndProc(Message& m)
  at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m)
  at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m)
  at System.Windows.Forms.NativeWindow.Callback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)

---

and here is my LoginForm code

Code:

---

            doctors.last_login = DateTime.Now;
            string srcConnString = null;
            var csBuilder = new SqlConnectionStringBuilder(srcConnString);
            csBuilder.Remove("Integrated Security");
            csBuilder.UserID = "sa";
            csBuilder.Password = "sasa";
            var connString = csBuilder.ToString();
            SqlConnection sqlcon = new SqlConnection("data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;user=sa;password=sasa;MultipleActiveResultSets=True;App=EntityFramework"");
            string query = "Select * from dbo.doctors Where doctors_username = '" + txtUsername.Text.Trim() + "' and doctors_password = '" + txtPassword.Text.Trim() + "'";
            SqlDataAdapter sda = new SqlDataAdapter(query, sqlcon);


            DataTable dbdoc = new DataTable();
            //sda.Fill(dbdoc);
            if (dbdoc.Rows.Count == 1)

            {
                FormMain objfrmMain = new FormMain();
                this.Hide();
                if(dbdoc.Rows[0][8].ToString()!="admin")
                 
                {
                    objfrmMain.MainMenuStrip.Items[0].Visible = false;
                    objfrmMain.MainMenuStrip.Items[2].Visible = false;
                    objfrmMain.MainMenuStrip.Items[3].Visible = false;
                    objfrmMain.MainMenuStrip.Items[4].Visible = false;
                    objfrmMain.MainMenuStrip.Items[5].Visible = false;
                    objfrmMain.MainMenuStrip.Items[8].Visible = false;
                   

                }
                objfrmMain.Show();

            }
            else
            {
                MessageBox.Show("Username-i ose passwordi eshte gabim !!!!!!!!!!!!!!!!!!!");
            }

           
                   
        }

---

You are using csBuilder to build a partial connection string (with no server or database info), and then assign it to connString... which you don't use (which means all of that code is effectively pointless).

You have a full connection string on the line that declares/sets the variable sqlcon , and that line includes integrated security=True; . change the True to False.


By the way, applications should very rarely (if ever) use the sa account, because it has full permissions. It is much better to create a new user for your application to use, and only assign appropriate permissions to it.

i have tryed integrated security=false but still have the same problem,i think the problem must be in sda.Fill(dbdoc);, what u supose me to do ?

Quote:

---

Originally Posted by ali3nn

i have tryed integrated security=false but still have the same problem,i think the problem must be in sda.Fill(dbdoc);, what u supose me to do ?

---

Could you show us the actual connection string you are using? As si has already pointed out your code seems to have two different connection strings being used.

If you set a breakpoint on the line

Code:

---

SqlDataAdapter sda = new SqlDataAdapter(query, sqlcon);

---

and in the debugger look at the inspect the sqlcon variable, what does it's ConnectionString property look like?

My connection string :

Code:

---

  <connectionStrings>
    <add name="dentnedEntities" connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string=&quot;data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework&quot;" providerName="System.Data.EntityClient" />
  </connectionStrings>

---

Quote:

---

Originally Posted by ali3nn

i have tryed integrated security=false but still have the same problem,i think the problem must be in sda.Fill(dbdoc);, what u supose me to do ?

---

The error message in the first post is definitely telling you the database server is refusing to let you log in, due to your connection string attempting to use a Windows login.

Note that sda.Fill uses sqlcon to connect, so sqlcon is the issue.


Go to http://www.connectionstrings.com/ and find yourself a valid connection string for your situation (change things like the server name and database as apt), and use it on the line that sets sqlcon.

Quote:

---

Originally Posted by ali3nn

My connection string :

Code:

---

  <connectionStrings>
    <add name="dentnedEntities" connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string="data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework"" providerName="System.Data.EntityClient" />
  </connectionStrings>

---

---

Oh dear... that is not what PlausiblyDamp told you to do, but in a way it is better you did this.

That connection string is different, and includes integrated security=True


You should work out a valid connection string (as explained in my previous post), and change it in both places.

How should i change the code that let me in connect to it.. ?

My connection string :

Code:

---

  <connectionStrings>
    <add name="dentnedEntities" connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string=&quot;data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework&quot;" providerName="System.Data.EntityClient" />
  </connectionStrings>

---

Quote:

---

Originally Posted by ali3nn

My connection string :

Code:

---

  <connectionStrings>
    <add name="dentnedEntities" connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string="data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework"" providerName="System.Data.EntityClient" />
  </connectionStrings>

---

---

That looks more like a connection string that would be used by an Entity Framework model, not one you would use directly with a SqlConnection object.

Could you please show us the current state of the code you are using or do what I asked and show us the connection string from the debugger. In fact if you could do both that would probably be even better.

Actually this project is using Entity Connection,I have 3 app.configs and they used this connection string,

Code:

---

<connectionStrings>
    <add name="dentnedEntities" connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string="data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework"" providerName="System.Data.EntityClient" />
  </connectionStrings>

---

and the login form i created uses the code that i already posted i think my code isnt right.. how should be a login form with entity? should they use the same connstring?

Actually this project is using Entity Connection,I have 3 app.configs and they used this connection string,

Code:

---

<connectionStrings>
    <add name="dentnedEntities" connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string="data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework"" providerName="System.Data.EntityClient" />
  </connectionStrings>

---

and the login form i created uses the code that i already posted i think my code isnt right.. how should be a login form with entity? should they use the same connstring?

Quote:

---

Originally Posted by ali3nn

Actually this project is using Entity Connection,I have 3 app.configs and they used this connection string,

Code:

---

<connectionStrings>
    <add name="dentnedEntities" connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string="data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework"" providerName="System.Data.EntityClient" />
  </connectionStrings>

---

and the login form i created uses the code that i already posted i think my code isnt right.. how should be a login form with entity? should they use the same connstring?

---

If you are really using that connection string then simply looking at it you will see that it has integrated security=True in there, so that certainly could be the source of the problem.

However that has nothing to do with the code you actually posted as your original post isn't using Entity Framework. Are you sure the error is happening in the bit of code you posted? If so please show us the current version of the code, if it isn't the failing code then show us the failing code.

Yeah actually the error is in the Loginform i havent this error before i created the login form..
here is all the code of LoginForm

Code:

---

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Data.SqlClient;
using System.Windows.Forms;
using System.Data.Entity;
using System.Data.Entity.SqlServer;



namespace DG.DentneD
{



    public partial class LoginForm : Form
    {
        public LoginForm()
        {
            InitializeComponent();
        }

        private void textBox2_TextChanged(object sender, EventArgs e)
        {

        }

        private void LoginForm_Load(object sender, EventArgs e)
        {
            label4.Text = DateTime.Now.ToString();
        }

        private void label3_Click(object sender, EventArgs e)
        {
            this.Close();
        }

        private void button1_Click(object sender, EventArgs e)


        {


            string srcConnString = null;
            var csBuilder = new SqlConnectionStringBuilder(srcConnString);
            csBuilder.Remove("Integrated Security");
            csBuilder.UserID = "sa";
            csBuilder.Password = "sasa";
            var connString = csBuilder.ToString();
            SqlConnection sqlcon = new SqlConnection("data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;user=sa;password=sasa;MultipleActiveResultSets=True;App=EntityFramework"");
            string query = "Select * from dbo.doctors Where doctors_username = '" + txtUsername.Text.Trim() + "' and doctors_password = '" + txtPassword.Text.Trim() + "'";
            SqlDataAdapter sda = new SqlDataAdapter(query, sqlcon);
         

            DataTable dbdoc = new DataTable();
            sda.Fill(dbdoc);
           
            if (dbdoc.Rows.Count == 1)

            {
                FormMain objfrmMain = new FormMain();
                this.Hide();
                if(dbdoc.Rows[0][8].ToString()!="admin")
                 
                {
                    objfrmMain.MainMenuStrip.Items[0].Visible = false;
                    objfrmMain.MainMenuStrip.Items[2].Visible = false;
                    objfrmMain.MainMenuStrip.Items[3].Visible = false;
                    objfrmMain.MainMenuStrip.Items[4].Visible = false;
                    objfrmMain.MainMenuStrip.Items[5].Visible = false;
                    objfrmMain.MainMenuStrip.Items[8].Visible = false;
                   

                }
                objfrmMain.Show();

            }
            else
            {
                MessageBox.Show("Wrong username or password !!!!!!!!!!!!!!!!!!!");
            }

           
                   
        }

        private void textBox1_TextChanged(object sender, EventArgs e)
        {

        }

        private void label2_Click(object sender, EventArgs e)
        {

        }

        private void label1_Click(object sender, EventArgs e)
        {

        }

        private void button2_Click(object sender, EventArgs e)
        {
            this.Close();
        }

        private void label4_Click(object sender, EventArgs e)
        {
            label4.Text = DateTime.Now.ToString();
        }

        private void label5_Click(object sender, EventArgs e)
        {

        }
    }
}

---

Yeah actually the error is in the Loginform i havent this error before i created the login form..
here is all the code of LoginForm

Code:

---

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Data.SqlClient;
using System.Windows.Forms;
using System.Data.Entity;
using System.Data.Entity.SqlServer;



namespace DG.DentneD
{



    public partial class LoginForm : Form
    {
        public LoginForm()
        {
            InitializeComponent();
        }

        private void textBox2_TextChanged(object sender, EventArgs e)
        {

        }

        private void LoginForm_Load(object sender, EventArgs e)
        {
            label4.Text = DateTime.Now.ToString();
        }

        private void label3_Click(object sender, EventArgs e)
        {
            this.Close();
        }

        private void button1_Click(object sender, EventArgs e)


        {


            string srcConnString = null;
            var csBuilder = new SqlConnectionStringBuilder(srcConnString);
            csBuilder.Remove("Integrated Security");
            csBuilder.UserID = "sa";
            csBuilder.Password = "sasa";
            var connString = csBuilder.ToString();
            SqlConnection sqlcon = new SqlConnection("data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;user=sa;password=sasa;MultipleActiveResultSets=True;App=EntityFramework"");
            string query = "Select * from dbo.doctors Where doctors_username = '" + txtUsername.Text.Trim() + "' and doctors_password = '" + txtPassword.Text.Trim() + "'";
            SqlDataAdapter sda = new SqlDataAdapter(query, sqlcon);
         

            DataTable dbdoc = new DataTable();
            sda.Fill(dbdoc);
           
            if (dbdoc.Rows.Count == 1)

            {
                FormMain objfrmMain = new FormMain();
                this.Hide();
                if(dbdoc.Rows[0][8].ToString()!="admin")
                 
                {
                    objfrmMain.MainMenuStrip.Items[0].Visible = false;
                    objfrmMain.MainMenuStrip.Items[2].Visible = false;
                    objfrmMain.MainMenuStrip.Items[3].Visible = false;
                    objfrmMain.MainMenuStrip.Items[4].Visible = false;
                    objfrmMain.MainMenuStrip.Items[5].Visible = false;
                    objfrmMain.MainMenuStrip.Items[8].Visible = false;
                   

                }
                objfrmMain.Show();

            }
            else
            {
                MessageBox.Show("Wrong username or password !!!!!!!!!!!!!!!!!!!");
            }

           
                   
        }

        private void textBox1_TextChanged(object sender, EventArgs e)
        {

        }

        private void label2_Click(object sender, EventArgs e)
        {

        }

        private void label1_Click(object sender, EventArgs e)
        {

        }

        private void button2_Click(object sender, EventArgs e)
        {
            this.Close();
        }

        private void label4_Click(object sender, EventArgs e)
        {
            label4.Text = DateTime.Now.ToString();
        }

        private void label5_Click(object sender, EventArgs e)
        {

        }
    }
}

---

The line

Code:

---

  SqlConnection sqlcon = new SqlConnection("data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;user=sa;password=sasa;MultipleActiveResultSets=True;App=EntityFramework"");

---

is creating a connection string with integrated security=true still, either use the SqlConnectionStringBuilder or set the connection string directly but as si pointed out previously, you aren't using the connection string generated by the builder. Fix the connection string and it should work.

Quote:

---

Originally Posted by PlausiblyDamp

The line

Code:

---

  SqlConnection sqlcon = new SqlConnection("data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;user=sa;password=sasa;MultipleActiveResultSets=True;App=EntityFramework"");

---

is creating a connection string with integrated security=true still, either use the SqlConnectionStringBuilder or set the connection string directly but as si pointed out previously, you aren't using the connection string generated by the builder. Fix the connection string and it should work.

---

Okay can u tell me how must the conn string be with SqlConnectionStringBuilder :sick:!

Thank u!

You don't need to use SqlConnectionStringBuilder (and aren't actually using it at the moment, that code just creates a value you ignore).

You can just use a connection string, as you are already doing in the line PlausiblyDamp quoted, you just need to put the correct values into it... and you already know that integrated security=True; is not correct. If you don't already know what your connection string should contain, then as I have said before, see post #6.

I must use this conn string

Code:

---

    <add name="dentnedEntities" connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string=&quot;data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework&quot;" providerName="System.Data.EntityClient" />

---

But the question is how should it be in login form.. and how to access the user and passwrd? user-type?

I must use this conn string

Code:

---

    <add name="dentnedEntities" connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string=&quot;data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework&quot;" providerName="System.Data.EntityClient" />

---

But the question is how should it be in login form.. and how to access the user and passwrd? user-type?

Quote:

---

Originally Posted by ali3nn

I must use this conn string

Code:

---

    <add name="dentnedEntities" connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string="data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework"" providerName="System.Data.EntityClient" />

---

But the question is how should it be in login form.. and how to access the user and passwrd? user-type?

---

That connection string is specific to the Entity Framework model and won't work with a standard SqlConnection object. If you are supposed to be using Entity Framework then presumably whoever created the project has already created an entity model that uses this connection string, however without seeing your solution it is going to be difficult for anyone here to give any specific advice.

Do you have access to the entity model in the solution (probably an edmx file)?

Quote:

---

Originally Posted by PlausiblyDamp

That connection string is specific to the Entity Framework model and won't work with a standard SqlConnection object. If you are supposed to be using Entity Framework then presumably whoever created the project has already created an entity model that uses this connection string, however without seeing your solution it is going to be difficult for anyone here to give any specific advice.

Do you have access to the entity model in the solution (probably an edmx file)?

---

Yes this is an open source project u can see the EntityModel HERE.and YES i have access to edmx file,the error is from loginForm i dont know how must the connection string for login mode?

Right, that changes things quite a bit....

If you are going to be working with that project then you really should be working with the functionality it provides or at least trying to follow it's patterns if you are going to extend things.

A quick glance through it seems to indicate the data access is done via the DentneDModel so you would do something like this to create an instance

Code:

---

DentneDModel dentnedModel = new DentneDModel();

---

I suspect something like

Code:

---

var res = dentnedModel.Doctors.FirstOrDefault(d => d.doctors_username == "user name" && d.doctors_password == "password");

---

might work as a login but it might be easier to contact the maintainer of the project and see if there is anything in the project to handle logins.

Quote:

---

Originally Posted by PlausiblyDamp

Right, that changes things quite a bit....

If you are going to be working with that project then you really should be working with the functionality it provides or at least trying to follow it's patterns if you are going to extend things.

A quick glance through it seems to indicate the data access is done via the DentneDModel so you would do something like this to create an instance

Code:

---

DentneDModel dentnedModel = new DentneDModel();

---

I suspect something like

Code:

---

var res = dentnedModel.Doctors.FirstOrDefault(d => d.doctors_username == "user name" && d.doctors_password == "password");

---

might work as a login but it might be easier to contact the maintainer of the project and see if there is anything in the project to handle logins.

---

Okay my Login form code must be like this yes

Code:

---

            string srcConnString = null;
            var csBuilder = new SqlConnectionStringBuilder(srcConnString);
            csBuilder.Remove("Integrated Security");
            csBuilder.UserID = "sa";
            csBuilder.Password = "sasa";
            var connString = csBuilder.ToString();

            DentneDModel dentnedModel = new DentneDModel();

            var res = dentnedModel.Doctors.FirstOrDefault(d => d.doctors_username == "user name" && d.doctors_password == "password");

            SqlConnection sqlcon = new SqlConnection("data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=FALSE ;user=sa;password=sasa;MultipleActiveResultSets=True;App=EntityFramework"");
            string query = "Select * from dbo.doctors Where doctors_username = '" + txtUsername.Text.Trim() + "' and doctors_password = '" + txtPassword.Text.Trim() + "'";
            SqlDataAdapter sda = new SqlDataAdapter(query, sqlcon);
         

            DataTable dbdoc = new DataTable();
            sda.Fill(dbdoc);

---

Or should i remove something ??

You should be using the entity model instead of the raw sql code something more like

Code:

---

DentneDModel dentnedModel = new DentneDModel();
var res = dentnedModel.Doctors.FirstOrDefault(d => d.doctors_username == txtUsername.Text.Trim() && d.doctors_password == txtPassword.Text.Trim());

---

instead of the code you already have.

Quote:

---

Originally Posted by PlausiblyDamp

You should be using the entity model instead of the raw sql code something more like

Code:

---

DentneDModel dentnedModel = new DentneDModel();
var res = dentnedModel.Doctors.FirstOrDefault(d => d.doctors_username == txtUsername.Text.Trim() && d.doctors_password == txtPassword.Text.Trim());

---

instead of the code you already have.

---

Aha okay but then it says the password is wrong when i use just use this line of code:

Code:

---

  DentneDModel dentnedModel = new DentneDModel();
            var res = dentnedModel.Doctors.FirstOrDefault(d => d.doctors_username == txtUsername.Text.Trim() && d.doctors_password == txtPassword.Text.Trim());

---

Quote:

---

Originally Posted by ali3nn

Aha okay but then it says the password is wrong when i use just use this line of code:

Code:

---

  DentneDModel dentnedModel = new DentneDModel();
            var res = dentnedModel.Doctors.FirstOrDefault(d => d.doctors_username == txtUsername.Text.Trim() && d.doctors_password == txtPassword.Text.Trim());

---

---

That looks like something a lot more specific to the application itself, have you checked the user name and password against what is in the database? Is the password hashed or similar?

Yes the username password is correct, But should we use another code or something to connect to it ?

Code:

---

            DataTable dbdoc = new DataTable();
            //sda.Fill(dbdoc);

              DentneDModel dentnedModel = new DentneDModel();
              var res = dentnedModel.Doctors.FirstOrDefault(d => d.doctors_username == txtUsername.Text.Trim() && d.doctors_password == txtPassword.Text.Trim());
           
            if (dbdoc.Rows.Count == 1)

            {
                FormMain objfrmMain = new FormMain();
                this.Hide();
                if(dbdoc.Rows[0][8].ToString()!="admin")
                 
                {
                    objfrmMain.MainMenuStrip.Items[0].Visible = false;
                    objfrmMain.MainMenuStrip.Items[2].Visible = false;
                    objfrmMain.MainMenuStrip.Items[3].Visible = false;
                    objfrmMain.MainMenuStrip.Items[4].Visible = false;
                    objfrmMain.MainMenuStrip.Items[5].Visible = false;
                    objfrmMain.MainMenuStrip.Items[8].Visible = false;
                   

                }
                objfrmMain.Show();

            }
            else
            {
                MessageBox.Show("Username-i ose passwordi eshte gabim !!!!!!!!!!!!!!!!!!!");
            }

---

My code but still deosnt work!!!!!!!!!!

Firstly if you are dealing with EF then the lines

Code:

---

DataTable dbdoc = new DataTable();
//sda.Fill(dbdoc);

---

are pointless and can be removed.

However in your code you are also doing

Code:

---

if (dbdoc.Rows.Count == 1)

---

which has nothing to do with the Entity Framework code and will never equal 1 as you are never loading any data into dbdoc, I suspect you should be checking if res != null but I am only really guessing.

I would suggest you take some time to get familiar with Entity Framework and the existing project before proceeding with your own modifications. If you are modifying existing code part of the process involves learning how it does things and figuring out what the best approach should be, just hacking away and trying to force your approach into an existing project is rarely going to be a success.

Quote:

---

Originally Posted by PlausiblyDamp

Firstly if you are dealing with EF then the lines

Code:

---

DataTable dbdoc = new DataTable();
//sda.Fill(dbdoc);

---

are pointless and can be removed.

However in your code you are also doing

Code:

---

if (dbdoc.Rows.Count == 1)

---

which has nothing to do with the Entity Framework code and will never equal 1 as you are never loading any data into dbdoc, I suspect you should be checking if res != null but I am only really guessing.

I would suggest you take some time to get familiar with Entity Framework and the existing project before proceeding with your own modifications. If you are modifying existing code part of the process involves learning how it does things and figuring out what the best approach should be, just hacking away and trying to force your approach into an existing project is rarely going to be a success.

---

Hello. thank u for ur advice my friend, i searched in google about entity framework conn how it must be but i cannot find nothing*
Here is my connection string* }

Code:

---

  <connectionStrings>
    <add name="dentnedEntities" connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string=&quot;data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework&quot;" providerName="System.Data.EntityClient" />
  </connectionStrings>

---

And from this conn string that is in my app config i need to provide a conn for login form like this one but i dont know how exactly it should be

Code:

---

DentneDModel dentnedModel = new DentneDModel("connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string="data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework"");

---

And then i have to reach db.doctors table doc_username&password,and then

Code:

---

If user type is = admin
{

}
else {

}

---

Does somebody know how must the code be thankyou.

If you are using the model then you can just create an instance of it, you don't need to pass the connection string in. If you look at any of the other places in the project where DentneDModel is being used you can see that this is the case.

Hmm.. explain a little how could it be??

Write me a code ?

I actually gave an example of how to create an instance of the class in post #23

As to actually validating the user name and password I suspect that is going to be a bit more difficult as the only example in that project is contained as part of the php application here and it appears to involve escaping both the username and password as part of the process.

My PHP is not really good enough to do more than skim that code so I am not sure how much help I would be.

Quote:

---

Originally Posted by PlausiblyDamp

I actually gave an example of how to create an instance of the class in post #23

As to actually validating the user name and password I suspect that is going to be a bit more difficult as the only example in that project is contained as part of the php application here and it appears to involve escaping both the username and password as part of the process.

My PHP is not really good enough to do more than skim that code so I am not sure how much help I would be.

---

Aha i really do not know how to use php login form for this project.. but all i want to do is creating a connection in my LoginForm* but it doesnt work anyway i do it.. its a little bit complicated* any of the codes doesnt work for me!

Quote:

---

Originally Posted by ali3nn

Aha i really do not know how to use php login form for this project.. but all i want to do is creating a connection in my LoginForm* but it doesnt work anyway i do it.. its a little bit complicated* any of the codes doesnt work for me!

---

I have created a new loginform..

Code here :

Code:

---

            DentneDModel dentnedModel = new DentneDModel();
            var res = dentnedModel.Doctors.FirstOrDefault(d => d.doctors_username == "user name" && d.doctors_password == "password");

---

And i checked the project found out this codes

Code:

---

        public string doctors_username { get; set; }

        public string doctors_password { get; set; }

---

my conn string in app.config

Code:

---

<connectionStrings>
    <add name="dentnedEntities" connectionString="metadata=res://*/Entity.Model_dentned.csdl|res://*/Entity.Model_dentned.ssdl|res://*/Entity.Model_dentned.msl;provider=System.Data.SqlClient;provider connection string=&quot;data source=DESKTOP-Q8526KR;initial catalog=dentned;integrated security=True;MultipleActiveResultSets=True;App=EntityFramework&quot;" providerName="System.Data.EntityClient" />
  </connectionStrings>

---

So do anyone knows how the code should be for the loginFORM? i added db do dataSource..!!!!!!

In your code you could try passing in a user name and password rather than just the strings "username" and "password"

Quote:

---

Originally Posted by PlausiblyDamp

In your code you could try passing in a user name and password rather than just the strings "username" and "password"

---

Okay so do u have any idea how to do it?

You mean something like the code I showed back in #25

I don't mean to be rude about this but how much programming experience do you have? Jumping into a large system like this one with multiple projects, EF / Repository patterns etc and trying to make changes isn't a simple or easy task and certainly not one I would have liked to do without quite a bit of experience or somebody to hand who knew the code base.

If you don't have much experience then it might be worth spending a bit of time to learn the basics of things like EF, Linq, etc. and getting yourself familiar with design patterns such as the repository pattern.

Quote:

---

Originally Posted by PlausiblyDamp

You mean something like the code I showed back in #25

I don't mean to be rude about this but how much programming experience do you have? Jumping into a large system like this one with multiple projects, EF / Repository patterns etc and trying to make changes isn't a simple or easy task and certainly not one I would have liked to do without quite a bit of experience or somebody to hand who knew the code base.

If you don't have much experience then it might be worth spending a bit of time to learn the basics of things like EF, Linq, etc. and getting yourself familiar with design patterns such as the repository pattern.

---

I have experience but ill need little help about it,so i will try to pass the value* if it doesnt work i come back here!