[resolved] retrieve the integer value after dividing by a number

hello i would like a code to retrieve the integer value
example after dividing a number , i got 100,6 and i would like 100 (or 101 if it is possible)
it 's to integrate in numericupdown.value
thanks for your answer

https://msdn.microsoft.com/en-us/lib...v=vs.110).aspx is probably what you are after.

i am a beginner i found round methode but i can't use it.Please help me with an example.

Try:

Code:

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intValue = Cint(Math.Floor(10/3))

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Here's a rounding example:

Code:

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'to get the integer value and discard the fractional part
Dim intValue As Integer = CInt(Math.Floor(10 / 3))
MsgBox(intValue)
'to use banker's rounding
intValue = CInt(Math.Round((10 / 4), MidpointRounding.AwayFromZero))
MsgBox(intValue)

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Quote:

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Originally Posted by .paul.

Try:

Code:

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intValue = Cint(Math.Floor(10/3))

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so resuming,
i have this addition: numericupdown3.value = numericupdown1.value+ (Cint(Math.Floor((numericupdown2.value) /2))

am i right?

That code will always round down. If you want midpoint rounding, see my second example...

Another thing you can do is use the integer divide \, rather than the floating point divide /. This does the round down, too, so you can write:

Code:

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numericupdown3.value = numericupdown1.value + numericupdown2.value \ 2

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That gives you the same result, since it will also always round down.

thank you very much! it works!:wave: