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Ok I am trying to do a duel boot to red hat linux and windows 2000. I have a 9.31 gb hard drive. Could someone help me out on like good sizes for each os, now primarly i will be useing windows 2k, so 2k will have the bigger partion...if i use one. Could some one just tell me a good way to do this.?
I did this with Win98 and Mandrake Linux, but used Partition Magic, which eases the pain of partitioning immeasurably.
I had a 5Gb Primary HDD for 98, and I paritioned a 30Gb secondary HDD into 9Gb for Linux and the rest as FAT for Win98 programs.
Now, if you're going to ask me for more technical details, you're stuffed, cos i read the manual from front to back.
To allow you to install plenty of packages, and perform a Full Installation, I would advise at least 2 GB, prefferably 3Gb for your Linux partition, and allocate the rest to Win2K, your primary OS.
I triple boot 98, 2k and RedHat... the 98 partition has 2.5gb, the 2k partition has 5gb, and the Redhat partition has 6gb(since the rest of the two drives are FAT32, I gave the linux more since it can't read FAT32)....
I use system commander to boot, it's really cool. It does partitions, and can make a hell of a lot of different kinds(NTFS, FAT, FAT32, Linux Native, BSD, BeOS, Etc.).
I've always been happy with plain old LILO!!
You want to leave some room for future programs, I would say a 35 - 40% partition for linux, then the rest for Windows2000.