[RESOLVED] Strange Behaviour in Format function while using Hex function in VB4

Can someone explain why the Format function refuses to put leading zeros in front of the hexadecimal numbers A thru F in this code? :)

Code:

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For idx = 1 To 15      ' actually need to loop to 1024
        TxtStr = Format(Hex(idx), "000")
    Next

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Is there a way to code this that will force the 'zeros' in front of the Hex number?

is txtstr dimmed as a string?
Why 3 0s hex values are even number of characters so 3 is strange. Unless of course you are trying to pad 3 0s in which case you need to add a 4th as 1 or more will be replaced by the value

You are saying: format a string to a string. Hex returns a string, not a number.
It would be similar result as: Format("X", "000")

One solution people generally use is to prefix the hex and take the right most n characters:

Code:

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Right$("00" & Hex(idx), 3)

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Thank You, my friend, it does exactly what I need. The original programmer was using "Format". I feel stupid to not have thought about the "Right" function (play on words :-) ). My silly work around was to just use three loops ... 1 to 15 , 16 to 255 . 256 to 1024 and prefix the correct number of zeros. See what happens when you don't use some language for 10 years!