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A little math question:
How many options are there for reaching the number 33 by adding with 6 numbers with the digits 0-9?
I mean, one of the options is: 5+5+6+6+8+3
another option is: 6+5+6+5+3+8
another option is: 4+7+2+9+9+2
How many options like these are there in total ?
Thanks.
the way to do this (can;t be bothered myself but hey!) is to express 33 as:
33=111111111111111111111111111111111
then, since you want 6 numbers, use 5x + signs:
33=1+1+1+1+1+1111111111111111111111111111
and find ocmbinations of this. take off the ones that aren;t less than 9 though.
get back to me if need more help/
I think you want to exclude zero - otherwise there are infinitely many combinations, because you can insert any number of zeroes in the list and not change the sum.
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