[RESOLVED] ANGLE OF INCIDENCE IS EQUAL TO THE ANGLE OF Reflection

hey is this true even when two balls meet?
is this the right way to get the answer?


To get the final angle:
AngleIncidence = AngleReflection
AngleIncidence = (180° + InitialAngle) - (NormalAngle)
AngleReflection = (NormalAngle) - (FinalAngle)
Solving for FinalAngle:
180 + Init - Norm = Norm - Final
180 + Init - 2 Norm = - Final
Final = 2 * Norm - 180 - Init


is the InitialAngle the angle between the two balls and if so does it matter if i get the angle from A to B first or B to A first?



i have the angle between B and A of 134 by 314 degrees when touching each other

ball B is moving at 23 degrees
ball A is moving at 229 degrees

how do i get the right reflextion angle for each ball?

thanks verry much

i guess what im asking is what is the (InitialAngle) and (NormalAngle) and (FinalAngle) ,im really lost here

hey yall
if line M =0 degrees
normal line is 90 degrees of that
incidence line is 135 degrees
if i use this formula below i get negitive numbers
why?


To get the final angle:
AngleIncidence = AngleReflection
AngleIncidence = (180° + InitialAngle) - (NormalAngle)
AngleReflection = (NormalAngle) - (FinalAngle)
Solving for FinalAngle:
180 + Init - Norm = Norm - Final
180 + Init - 2 Norm = - Final
Final = 2 * Norm - 180 - Init

If two balls meet the angle of incidence and reflection are given by the shared tangent at collision which is of course at right angles to the line drawn between the centres of the two spheres (assuming that they are the same size!) The initial angle of travel is therefore far less important than the point at which they meet and the size of the balls. Only in the ideal case (zero dimension balls) will the tangent necessarily bisect the angle between the lines of travel.

So in the ideal case, two objects approaching each other at an angle of 50 degrees, would each have an effective angle of incidence of 25 degrees to the bisector and would reflect along along a line of 155 degrees from the bisector. To get these vectors relative to the plane on which the collision takes place will obviously require an adjustment relative to a predetermined line.

I'm really not sure I follow the logic of your calculation method at all. AI = AR is simply absolute. There's no useful calculation to be done unless one wants to chart the absolute path within a frame of reference such as the compass points and that's a very simple adjustment to take account of the angle of the 'mirror'.

A ball travelling from the SE hits a wall running E-W the angle of incidence is 135 - 90 = 45. The outgoing path is therefore 270 - 45 = 225 better known as SW.

on computers 90 degrees is down ,or is that just for 3d stuff?
and thank you so much ,i new the answer,i just couldnt get te fourmla right.
i was having trouble getting a real life looking bounce ,from all angles.
thanks

what if the angle of incidence is 45 ,do i plus it?

many thanks to dunfiddlin i think after alot of trys i got it thanks