How do you prove this:
I've been banging my head about it, help :rolleyes:Code:(a^x)' = a^x * ln(a)
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How do you prove this:
I've been banging my head about it, help :rolleyes:Code:(a^x)' = a^x * ln(a)
y = a^x
ln(y) = x*ln(a)
d[ ln(y) ]/dx = ln(a)
(1/y)*dy/dx = ln(a)
dy/dx = ln(a)*y
dy/dx = ln(a)*a^x
WOO!
Thanks a lot, why didn't I think of taking the natural logarithm of both sides :rolleyes: