[RESOLVED] Change string value from a function?

Is it possible to change the value of a string from a function, because I'm having a problem here?
The general idea would be like below, but the string will not change, so is there any way I make that happen?

vb.net Code:

Public Class Form1
 
Dim MyItem1, MyItem2, MyItem3 As Integer
 
Public Function SetItemStats(ByVal CurrentItemSlot As ComboBox, ByVal CurrentItemName As String)
        CurrentItemName = CurrentItemSlot.Text
End Function
 
Private Sub SetItem1Button_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles SetItem1Button.Click
        SetItemStats(item1list, MyItem1) ' item1list is the name of my combobox.
        MsgBox(MyItem1) ' Comes out empty here
End Sub
 
End Class

EDIT: Fixed that by changing ByVal into ByRef, I'm such an idiot.

there are 2 problems there:

Code:

---

Public Function SetItemStats(ByVal CurrentItemSlot As ComboBox, ByVal CurrentItemName As String)
    CurrentItemName = CurrentItemSlot.Text
    'no return???
End Function

---

try this instead:

Code:

---

Public Sub SetItemStats(ByVal CurrentItemSlot As ComboBox, ByRef CurrentItemName As String)
    CurrentItemName = CurrentItemSlot.Text
End Sub

---

Quote:

---

Originally Posted by .paul.

there are 2 problems there:

Code:

---

Public Function SetItemStats(ByVal CurrentItemSlot As ComboBox, ByVal CurrentItemName As String)
    CurrentItemName = CurrentItemSlot.Text
    'no return???
End Function

---

try this instead:

Code:

---

Public Sub SetItemStats(ByVal CurrentItemSlot As ComboBox, ByRef CurrentItemName As String)
    CurrentItemName = CurrentItemSlot.Text
End Sub

---

---

Yeah, changing it into ByRef fixes it. Anyway, is there a problem if I leave it as a function? I know since it doesn't return anything it should be a Sub, but I prefer using the word function instead of sub, or just adding a Return 0 maybe :D

Thanks btw.

you can leave it as a function + return an unused value if you add a return type

Yeah, doing that. Thanks again and marking as solved now.