Mid??

What would be the equivalent of :

For x = 0 To (Len(bin) - 1)
If Mid(bin, Len(bin) - x, 1) = "1" Then CDecimal = CDecimal + (2 ^ x)
Next x

in c++?? thx. :):):):)

Things like this are a lot easier to do if you think of your standard C string as an array:

Code:

---

char *pcBin = "10101";
int iTemp = 0'

for(int i = 0; i < strlen(pcBin); i++) {
    if(pcBin[i] == '1')
        iTemp += 1 << i;
}

---

Than Parksie, but how come i dont get the same answer with the function u gave me?

What would :

iTemp = iTemp + (2^i)

be in c++?

You use the shift operators << and >> :)
For example 1 << 2 = 1 * 2^2

It's much easier to see when you look in binary. They shift everything one bit to the left or the right:
b0101010 << 1 = b1010100
b0101010 >> 3 = b0000101

This is why 2^i disappeared in my code. Anyway, what "different answer" did you get?

I am writing a dll that will send data to the parallel port. The functions in the dll will then be used in VB. I already have the funcs to do the conversions in vb, but i want to include them into my dll. (these funcs were the ones i posted in the Parallel Port-Urgent" thread. I AM USING 8-BIT BINARIES.

I thought
00000001 was 1
00000010 was 2
00000011 was 3
00000100 was 4
00000101 was 5
etc...

When i use the code you gave me when I put

00000101 it shows 6
or for:
11111111 it shows 0 instead of 255.

For example, i would get 255 for 11111111 in vb.

SORRY. My mistake. I was reading ion wrong way.
what a $#?@ i am! :) Thanks a lot. Also, how would i convert from a decimal to a binary, the same thing you gave me but vice-versa?

So
iTemp += 1 << i;

would be iTemp = iTemp + 2^i

in VB?

That's correct :)

Thanks a lot. May I ask you one more thing?:
how would I write a function thst would now convert from decimal to a binary?

Code:

---

long Dec2Bin(long lNum, char *pcBuf) {
    int i = 0;

    while(lNum) {
        if(lNum & 1) pcBuf[i] = '1';
        else pcBuf[i] = '0';
        lNum >>= 1;
        i++;
    }
    pcBuf[i] = 0; // Null-terminated

    return i;
}

void userfunc() {
    char pcBuf[40];
    Dec2Bin(27, pcBuf);
    cout << pcBuf << endl;
}

---

Thanks a lot. I actually wasn't too far from that :) Anyways, thans a lot, Parksie:);) :p :) ;) :p :p :) :D :D

No problem :)

PortBits%(I) = PortNum% Mod 2
PortNum% = Fix(PortNum% / 2)

in c++? What would the Fix be?

Just cast it straight to an integral value to lose the fractional portion:

Code:

---

float fNum = 5.4f;
int iOther = (int)fNum;

cout << iOther << endl;

---

...produces "5" :)

Sorry if I annoy you, but for the dec2bin function, what should i change so that it display the "0" all the time.
eg: now if i put 3 it s gonna say 11
how would i change it so that it outputs 00000011?