[RESOLVED] exit a php function in middle and continue other lines of code

hi,
i have this code

Code:

---

<?php
  echo "HELLO";
  abc();
  echo "WORLD";
?>

<?php
function abc()
{
    if(true)
  {
      exit(0);
  }
}
?>

---

it outputs only HELLO

but i want it to print

HELLO WORLD

It does not print world due to the exit function in the function... Please help me to get it work even if exit is executed... :-(

I'm guessing what you're looking for is 'return' and not 'exit'.

'return' is a language construct that allows you to exit a function (with possible return value).
'exit' is a function that stops execution for the entire script.

Quote:

---

Originally Posted by TheBigB

I'm guessing what you're looking for is 'return' and not 'exit'.

'return' is a language construct that allows you to exit a function (with possible return value).
'exit' is a function that stops execution for the entire script.

---

i also tried return, But php keep doing something after return, it executes the whole code and then return. and that cause script to failure Maximum Execution Time 30 Seconds ( Error Comes )

Quote:

---

PHP Code:

---

if(true) 


---

---

This has no meaning.

PHP Code:

---

function abc()
{
  return;
} 


---

This also has no meaning. It is the same as:

PHP Code:

---

function abc() {} 


---

This:

PHP Code:

---

function abc() {}

echo 'HELLO';
abc();
echo 'WORLD'; 


---

will output:

Code:

---

HELLOWORLD

---

Quote:

---

But php keep doing something after return, it executes the whole code and then return. and that cause script to failure Maximum Execution Time 30 Seconds ( Error Comes )

---

This means you have created an infinite loop.

Post the code that you tried.

Am I write assuming you want something like this:

PHP Code:

---

<?php
  abc1(false);
  echo "HELLO";
  abc1(true);
  echo "WORLD";

function abc1($doIt)
{
  if($doIt) {
    return;
  }
  echo "&"; // This doesn't get run if $doIt == true but the script continues
}
?>
OUTPUT:
&HELLOWORLD

---

Or:

PHP Code:

---

<?php
  abc2(false);
  echo "HELLO";
  abc2(true);
  echo "WORLD";

function abc2($doIt)
{
  if($doIt) {
    exit(0);
  }
  echo "&"; // This doesn't get run if $doIt == true but also the whole script stops.
}
?>
OUTPUT:
&HELLO

---

i have noticed, that return still continues to the end of the loop, i just want to come out of the function and then continue rest script

here is the code

Code:

---

<?php
$prev_root;
function print_given_level($root, $level)
{
        global $prev_root;
          $sql = "SELECT * FROM tbl_users where business_id= '$root' ";
        $res = mysql_query($sql);
        $row = mysql_fetch_array($res);
                if($root < 1)
                {
                        // return 0;
                        echo "<font color='red'>END OF THE TREE Last Root Value $prev_root</font>";
                        exit(0);
                }                       
                if($level == 1)
                        echo "<hr> EMAIL  =  ".$row['email'] ; 
                else if($level > 1)
                {
                        $prev_root = $root;
                        echo "<br> Going to process Left Node (Level) $level = ". ($level -1) . "<br>";
                        print_given_level($row['left_leg_assigned_to'], $level - 1);   
                        echo "<br> Going to process Right Node (Level) $level = ". ($level -1) . "<br>";                       
                        print_given_level($row['right_leg_assigned_to'], $level - 1);                       
                }
       
}
?>

---

i have just found a temp solution for now, to redirect to another page instead of exit;

Ah... you didn't mention recursion.

Returning does exit the function. The problem is that you're expecting it to exit the whole recursion loop, but instead what it actually does is exit the current stack frame only.

One technique you could use is to return a value (true or false) to indicate whether or not to continue recursing:

PHP Code:

---

<?php
$prev_root;
function print_given_level($root, $level)
{
    global $prev_root;
    $sql = "SELECT * FROM tbl_users where business_id= '$root' ";
    $res = mysql_query($sql);
    $row = mysql_fetch_array($res);
    if($root < 1)
    {
        echo "<font color='red'>END OF THE TREE Last Root Value $prev_root</font>";
        return false;
    }            
    if($level == 1)
        echo "<hr> EMAIL  =  ".$row['email'] ;   
    else if($level > 1)
    {
        $prev_root = $root;
        echo "<br> Going to process Left Node (Level) $level = ". ($level -1) . "<br>";
        if (!print_given_level($row['left_leg_assigned_to'], $level - 1))
            return false;
        echo "<br> Going to process Right Node (Level) $level = ". ($level -1) . "<br>";            
        if (!print_given_level($row['right_leg_assigned_to'], $level - 1))
            return false;
    }
    
    return true;
}
?>

---

Traversing a tree can be done without recursion, but it is not as intuitive.

Also, you avoid using echo to emit HTML.

Also also, it strikes me that you might be able to avoid recursion altogether (and many queries) if you restructured your database.

yes,
it works now :-)
Thank you penagate

Hi,
i don't know why i can't get out of the loop from the specific place only.

is it possible to exit from the recursive function below and process other task in the script ? without using of exit(0) function?

Please make it out after printing the red line in the code.

Code:

---

<?php
$prev_root;
function print_given_level($root, $level)
{
    global $prev_root;
                                        if( $the_level != $current_level )
                                        {

                                                if($is_L_found == "empty")
                                                {
                                                        echo "Print_Something_here L And Exit";
                                                        return false;                                                       
                                                        //exit(0);
                                                }
                                       
                                                if($is_R_found == "empty")
                                                {
                                                        echo "Print_Something_here R And Exit";
                                                        return false;                                                       
                                                        //exit(0);                                                       
                                                }
                               
                                        }       
    $sql = "SELECT * FROM tbl_users where business_id= '$root' ";
    $res = mysql_query($sql);
    $row = mysql_fetch_array($res);
    if($root < 1)
    {
        echo "<font color='red'>END OF THE TREE Last Root Value $prev_root</font>";
        return false;
    }           
    if($level == 1)
        echo "<hr> EMAIL  =  ".$row['email'] ; 
    else if($level > 1)
    {
        $prev_root = $root;
        echo "<br> Going to process Left Node (Level) $level = ". ($level -1) . "<br>";
        print_given_level($row['left_leg_assigned_to'], $level - 1)
           
        echo "<br> Going to process Right Node (Level) $level = ". ($level -1) . "<br>";           
        print_given_level($row['right_leg_assigned_to'], $level - 1)
           
    }
   
    return true;
}
?>

---

:mad:

You need to check the return value like I did in post 7.

yes got it working. :-) thank you