char replace

hi
im trying to change char in a text block but i cant get it to work.
can somone please help
the text is taken of another website and formatted. taking out any links and doubling " and ' so it can be added to my database (mysql)

i got this

PHP Code:

---

$Temp = strip_tags($plot[1], '<br>');
    $Temp2=str_replace('"','""',$Temp);
    $plott[1]=str_replace("'","''",$Temp2); 


---

You're going to have to be more descriptive. What are you putting in (value of $plot[1] before your replacement code) and what are you getting out (value of $plott[1] at the end of your code)? You can help yourself troubleshoot by echo'ing out the results each step of the way:

PHP Code:

---

echo $plot[1] . "\n\n";
$Temp = strip_tags($plot[1], '<br>');
echo $Temp . "\n\n";
$Temp2=str_replace('"','""',$Temp);
echo $Temp2 . "\n\n";
$plott[1]=str_replace("'","''",$Temp2);
echo $plott[1] . "\n\n"; 


---

At which point are you not getting what you expected for the output?

hi i solved my problem by using the following

Code:

---

$Find = array("'",'"');
                            $ee =$plot[1], '<br>';
                            $plot[1] =  str_replace($Find,"",$ee);

---

hi
but now i have come across another problem with the same code..

PHP Code:

---

# Locations
  $locs = $movie->locations();
  if (!empty($locs)) {
    ++$rows;

    foreach ($locs as $loc) {
      if ( empty($loc['url']) );
      else ;
      }

  }
   //this is the main txt im trying to filter this is from $ee
  //St. Luke's Hospital - 2632 E. Washington Street, Pasadena, California, USA
 //--- 

                             $Find = array("'",'"');
                             $ee =$loc['name'];
                             $locationsname =  str_replace($Find,"",$ee); 


---

when i use the txt im trying to filter direct in to the filter for example.

PHP Code:

---

$ee="St. Luke's Hospital - 2632 E. Washington Street, Pasadena, California, USA"; 


---

the filter works but when im using the text direct from $loc['name']; the filter dont work

.. wait. the entire point of all of this is to eventually add this data to the database, correct? don't use str_replace() at all then. use an escape function, like mysql_real_escape_string():

PHP Code:

---

$mysql_safe_loc = mysql_real_escape_string($loc['name']); 


---

then, use it in your query:

PHP Code:

---

$sql = "INSERT INTO locations (name) VALUES ('{$mysql_safe_loc}');"; 


---

hi kows
i never thought to look at sql code. i have now changed it to the

PHP Code:

---

mysql_real_escape_string(); 


---

and works perfect. it will take me some time to sort the rest of my code to this.

thanks again kows you have been a big help on this as im still learning all this php coding:thumb::thumb::thumb: