[RESOLVED] Regular Expression Help Needed

Hey guys,

I am in a need of a Regular Expression to restrict input to only certain characters in a text box. Any help would be gretly appreciated.

The text box can only allow 0 or 1 "+" sign at the beginning and at no other position.
The text box can only allow 0 or 1 ":" sign not before the "+" sign.
The text box can allow any number of 0-9 digits.

e.g.

10 = GOOD
+10 = GOOD
+:10 = GOOD
:10 = GOOD
12:20 = GOOD
+12:20 = GOOD

No other characters allowed.

Hope this makes sense.

TA :)

Should work:

Code:

---

\+*:*\d{2}(:*\d{2})*

---

I assumed that only 2 digits in a row are allowed {2}
If you want any number of digits, i.e. 23432:2342342 then it would be:

Code:

---

\+*:*\d*(:*\d*)*

---

Thanks.

I tried that but it allows for "15:15:15" which is more than 1 ":" characters.

Well, then try this:

Code:

---

\+*:*\d{2}(:*\d{2}){0,1}

---

Thanks. But I am still having issues with it so finally managed to did it my way!

Anyways here it is with tiny errors.

Code:

---

\+{0,1}\d{1,3}|\+{0,1}:{0,1}\d{1,3}|\+{0,1}\d{1,2}:{0,1}\d{1,2}

---

The only problem is, it allows +7777 where I don't want the integer value to go beyond 3 characters so it should stop at + 777.

Can someone please help me?

Try this expression:

vb Code:

"^\+?(?::\d*|\d*:)?\d*"

Thanks Zach :)

For some reasons the input control I am using to restrict the user input is causing it to throw a syntex error! Even the though the RegEx parser knows it is correct.

Can you help me with the one I posted?

Try this (replace TextBox1 with your textbox's name)

Code:

---

Try
        If Regex.IsMatch(TextBox1.Text, "\A(?:^\+?(?::\d*|\d*:)?\d*)\Z") Then
                ' Successful match
        Else
                ' Match attempt failed
        End If
Catch ex As ArgumentException
        'Syntax error in the regular expression
End Try

---

I would but the specific control I use, allows me to use RegEx as a mask to restrict user input which what I am after.

Try the regex I posted in post #6... or try this:

vb Code:

"\A(?:^\+?(?::\d*|\d*:)?\d*)\Z"

Cool thanks. I got it all working.