[RESOLVED] Random Letters and Number

Hello everyone .

I wonna make a Password Generator, something like a 15 digits password . I know that I must use a "For i = 1 to 15" to repeat the code, but I'd like to know how I can randomize both numbers and letters.

Thanks in advance .

Code:

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Dim I As Long
Dim strPassword As String
Dim intChar As Integer

For I = 1 to 15
  Do
      intChar = Int(Rnd * 75 + 48)
  Loop Until (intChar >= Asc("0") And intChar <= Asc("9")) Or (intChar >= Asc("A") And intChar <= Asc("Z")) Or (intChar >= Asc("a") And intChar <= Asc("z"))

  strPassword = strPassword & Chr(intChar)
Next I

Debug.Print strPassword

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In the Form's Load event call:

Randomize

Build a form with a label and a command button. Then apply this code:

Code:

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Private Sub Command1_Click()
Dim PassWord As String, RanNum As Integer, RanChar As String
For I = 1 To 15
    Do
        RanNum = Int(76 * Rnd + 47)
        Select Case RanNum
        Case 48 To 57, 65 To 90, 97 To 122
            Exit Do
        Case Else
        End Select
    Loop
    PassWord = PassWord & Chr$(RanNum)
Next
Label1.Caption = PassWord
End Sub

Private Sub Form_Load()
Randomize
Label1.Caption = vbNullString
End Sub

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This code produces 15-character random passwords containing numbers and both upper- and lower-case letters positioned randomly within the password. I assume that is what you wanted.

Really Helpfull guys.
Thanks =)

A bit late, but for possibly interested here is a non-specialized, generic function that can be built on the idea:

Code:

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Public Function StrRnd(ByVal Length As Long, Optional Chars As String = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ") As String
    Dim I As Long
    StrRnd = Space$(Length)
    For I = 1 To Length
        Mid$(StrRnd, I, 1) = Mid$(Chars, Int(Rnd * Len(Chars)) + 1)
    Next I
End Function

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To get the same results as above you'd call this like:

MsgBox StrRnd(15, "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz")

Quote:

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Originally Posted by Merri

A bit late, but for possibly interested here is a non-specialized, generic function that can be built on the idea:

Code:

---

Public Function StrRnd(ByVal Length As Long, Optional Chars As String = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ") As String
    Dim I As Long
    StrRnd = Space$(Length)
    For I = 1 To Length
        Mid$(StrRnd, I, 1) = Mid$(Chars, Int(Rnd * Len(Chars)) + 1)
    Next I
End Function

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To get the same results as above you'd call this like:

MsgBox StrRnd(15, "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz")

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Nice idea, Merri. Build the string first and select the Mid$() randomly. That eliminates the Do...While loop and rejected random numbers. The big string can be produced at Form Load and stored Public. Here's a revision to my code based on what I learned by studying yours:

Code:

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Dim BigStr As String
Private Sub Command1_Click()
Dim PassWord As String
PassWord = Space$(15)
For I = 1 To 15
    Mid$(PassWord, I, 1) = Mid$(BigStr, Int(Rnd * Len(BigStr) + 1), 1)
Next
Label1.Caption = PassWord
End Sub

Private Sub Form_Load()
Randomize
Label1.Caption = vbNullString
For I = 48 To 122
    Select Case I
    Case 48 To 57, 65 To 90, 97 To 122
        BigStr = BigStr & Chr$(I)
    Case Else
    End Select
Next
End Sub

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Note, rather than typing an enormous string take a look at my Form Load.