[RESOLVED] Open/Saving textbox values

hey guys...My windows form as a bunch of textboxes on it that basically let the user put in different positions/forces that a test cycle then uses. I am trying to let the user save their profile settings/open the settings so they don't have to input the same values every time they want to run the same test. Here is my code so far. basically, when i save my csv file, and open it, all 6 textbox values are plopped in the first textbox instead of being distributed to their original boxes. I just read about a "split" function that I am going to read up on and see if that will help, but in the meantime, PLEASE HELP! Keep in mind i am a beginner and this is my first exposure with the save/openfileDialog classes...Thanks guys. I know you'll help out.

code Code:

Private Sub SaveProfileToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles SaveProfileToolStripMenuItem.Click
        SaveProfileDialog.ShowDialog()
 
        Dim sw As StreamWriter
 
        Try
            With SaveProfileDialog
                .FileName = FileName
                .Filter = "CSV files (*.csv)|*.csv|" & "All files|*.*"
                If .ShowDialog() = DialogResult.OK Then
                    FileName = .FileName
 
                    sw = New StreamWriter(FileName)
 
                    sw.Write(Position1.Text)
                    sw.Write(Position2.Text)
                    sw.Write(Position3.Text)
                    sw.Write(Position4.Text)
                    sw.Write(Position5.Text)
                    sw.Write(Position6.Text)
 
                End If
            End With
        Catch es As Exception
            MessageBox.Show(es.Message)
        Finally
            If Not (sw Is Nothing) Then
                sw.Close()
            End If
        End Try
 
    End Sub
 
    
 
 
    Private Sub OpenProfileToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles OpenProfileToolStripMenuItem.Click
        Dim sr As StreamReader
        Try
            With OpenProfileDialog
             
                .Filter = "CSV files (*.csv)|*.csv|" & "All files|*.*"
               
                If .ShowDialog() = DialogResult.OK Then
 
                    FileName = .FileName
                    sr = New StreamReader(.OpenFile)
 
                    Position1.Text = sr.Read
 
                End If
            End With
        Catch es As Exception
            MessageBox.Show(es.Message)
        Finally
            If Not (sr Is Nothing) Then
                sr.Close()
            End If
        End Try
    End Sub

ok, i think the split function helped somewhat, but it still isn't quite working...see the code below.

vb Code:

Private Sub OpenProfileToolStripMenuItem_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles OpenProfileToolStripMenuItem.Click
        Dim sr As StreamReader
        Try
            With OpenProfileDialog
             
                .Filter = "CSV files (*.csv)|*.csv|" & "All files|*.*"
               
                If .ShowDialog() = DialogResult.OK Then
 
                    FileName = .FileName
                    sr = New StreamReader(.OpenFile)
                    Dim str
                    str = Split(Filename, ",")
                    Dim i As Integer
                    For i = 0 To UBound(str)
                        Position1.Text = str(0)
                        Position2.Text = str(1)
                        Position3.Text = str(2)
                        Position4.Text = str(3)
                        Position5.Text = str(4)
                        Position6.Text = str(5)
 
                    Next
                End If
            End With
        Catch es As Exception
            MessageBox.Show(es.Message)
        Finally
            If Not (sr Is Nothing) Then
                sr.Close()
            End If
        End Try
    End Sub

basically all I am getting is my filename as a string in the first textbox, which makes sense, but how do I split the contents of the file instead of the filename itself? Then my code will work.

nevermind guys. i think i got it. i just sent the data to another string and then split that string instead of trying to split the contents of the file directly.