[RESOLVED] Detect asci!

Hi I saw somewhere in this forum a post about detecting and outputting the asci for a keypress.... how is that?


explination:
If i press "ENTER" then the asci code for ENTER should be returned... as a msgbox for me to read...

Private Sub Text1_KeyPress(KeyAscii As Integer)
MsgBox KeyAscii
End Sub

Ohh wait i forgott some part of the code =)

What do you mean?

works perfectly tanks =)

Oh OK. You're welcome. :)

how can i use this in a if statement? so like:

Code:

---

if asci = 113 then
text.text = text.text & a
end if

---

q = ascii 113...

Code:

---

Private Sub Text1_KeyPress(KeyAscii As Integer)
    If KeyAscii = 113 Then
        MsgBox "You Pressed Q!"
    End If
End Sub

---

what if i use check this from the commandbutton?



I type in q in a textbox and then press enter

Code:

---

Command1_click
if asci = 113 then
'add a to the textbox
end if

---

Is this what you are looking for ?

Code:

---

Private Sub Command1_Click()
  MsgBox "Command button pressed"
End Sub

Private Sub Text1_KeyPress(KeyAscii As Integer)
  If KeyAscii = 13 Then    '~~~ User pressed Enter Key
    Command1.Value = True
  End If
End Sub

---

...:wave:

What are you trying to accomplish? If you explain, I might be able to help better. Do you just want to check if "q" exists at all in the textbox? you can use Instr for that.

Aight let me say something like enigma!

If you type Q it will change ure Q to A...

The user enters a password into the textbox...
when the user press enter the asci for each char in the word will be checked and replaced with another of choice (from Db later on)

Hope this explains...:bigyello:

OK so you want to validate it when the user presses enter. Here is one way to do it:

Code:

---

Private Sub Text1_KeyPress(KeyAscii As Integer)
    If KeyAscii = vbKeyReturn Then
        Text1.Text = Replace$(Text1.Text, "Q", "A")
    End If
End Sub

---

Alternative idea:

Code:

---

Private Sub Text1_KeyPress(KeyAscii As Integer)
  If KeyAscii = 13 Then      '~~~ If EnterKey is pressed
 
    Dim i As Long
    Dim Temp As Integer
    Dim strText As String
   
    strText = Text1.Text      '~~~ Storing a copy of the Text in a variable
   
    For i = 1 To Len(strText) '~~~ Looping through each characters
      Temp = Asc(Mid$(strText, i, 1)) '~~~ ASCII value of the character is obtained
      Select Case Temp
        Case 113:
          Temp = 100
        Case 112:
          Temp = 65
        '...etc
        End Select
        Mid$(strText, i, 1) = Chr$(Temp)  '~~~ Replace the character with the new one
    Next i
    Text1.Text = strText          '~~~ Write back to the TextBox
  End If
End Sub

---

...:wave:

Yes that would be a better idea if you have many replacements to make.

vb Code:

Private Cryptobet(25) As Byte
 
Private Sub InitCrypt()
Dim X As Long, Y As Long, bTMP As Byte
Rnd -1 'reset rnd generator
Randomize 5330 'SEED
 
'assign the alphabet to the array
For X = Asc("a") To Asc("z") 'asc("a") = 97, so subtract that to normalize the values to 0-25
  Cryptobet(X - 97) = X
Next X
 
'shuffle it
For X = 1 To UBound(Cryptobet) 'loop though the array
  Y = Int(X * Rnd) 'get a random whole number
  If X <> Y Then
    bTMP = Cryptobet(X) 'store one value in tmp var
    Cryptobet(X) = Cryptobet(Y) 'swap direct
    Cryptobet(Y) = bTMP 'swap with temp
  End If
Next X
End Sub
 
Private Function EnCrypt(ByVal strIn As String) As String
Dim bString() As Byte
Dim bNewString() As Byte 'a couple of dynamic byte arrayss
 
bString = StrConv(LCase$(strIn), vbFromUnicode) 'convert BSTR to ascii/byte array
ReDim bNewString(UBound(bString)) 'make a ascii/byte array to store the result
 
For X = 0 To UBound(bString)
  bNewString(X) = Cryptobet(bString(X) - 97) 'basic LUT
Next X
EnCrypt = StrConv(bNewString, vbUnicode) 'convert the ascii array to BSTR(a normal 'as String' type)
End Function
 
'usage:
 
Private Sub Command1_Click()
InitCrypt
Debug.Print EnCrypt("helloworld")
End Sub

This doesn't handle anything outside of a-z, and doesn't check for such things(they'll cause an error).

Could easily be expanded to the entire ascii character set.

aight not really what i needed but you all seem to get the point =), I need to check as i press the button... command1 when i press that then check...
Maybe should use a function or so?

You could call EnCrypt with Lcase$(Chr$(Keyascii)), and then set Keyascii to the Asc() of the returned value. And/Or just use the array as a LUT.

Like:
keyascii = Asc(EnCrypt(Lcase$(Chr$(keyascii))))

Or:

keyascii = Cryptobet(Asc(Lcase$(Chr$(keyascii)))-97)

Tested, and either way works. Just don't try to use a character outside a-z without updating the Cryptobet.

well i cant take ure cryptobet as im about to make my own "crypting program" (Not to be a real program only messing around and learning)
So i only wonder if it would be possible if i made a function maybe called Enigma...
I call enigma like Enigma text1.text and as my program goes it returns the enigma to an variable or directrly into text2.text... ?

Would this be possible and if so a little push to get the function working so i call the "detect asci"

Hope this makes abit sense atleast... Hard to explain

//Thomas

You could do something like this:
This sub takes a textbox as a parameter and changes the text in it.

Code:

---

Public Sub Enigma(objText As TextBox)
    objText.Text = objText.Text & " modified!"
End Sub

Private Sub Command1_Click()
    Enigma Text1
End Sub

---

OR:

This function takes any string, changes it, then returns the value.

Code:

---

Public Function Enigma(ByVal sText As String) As String
    sText = sText & " modified!"
    Enigma = sText
End Function

Private Sub Command1_Click()
    Text1.Text = Enigma(Text1.Text)
End Sub

---

You can always change:

Code:

---

For X = Asc("a") To Asc("z") 'asc("a") = 97, so subtract that to normalize the values to 0-25
  Cryptobet(X - 97) = X
Next X

---

With an unrolled equivalent. Setting each Cyprobet() index manually, just make sure you don't forget any characters.

Here's the same code, unrolled:

vb Code:

'index = ascii value
Cryptobet(0) = 97
Cryptobet(1) = 98
Cryptobet(2) = 99
Cryptobet(3) = 100
Cryptobet(4) = 101
Cryptobet(5) = 102
Cryptobet(6) = 103
Cryptobet(7) = 104
Cryptobet(8) = 105
Cryptobet(9) = 106
Cryptobet(10) = 107
Cryptobet(11) = 108
Cryptobet(12) = 109
Cryptobet(13) = 110
Cryptobet(14) = 111
Cryptobet(15) = 112
Cryptobet(16) = 113
Cryptobet(17) = 114
Cryptobet(18) = 115
Cryptobet(19) = 116
Cryptobet(20) = 117
Cryptobet(21) = 118
Cryptobet(22) = 119
Cryptobet(23) = 120
Cryptobet(24) = 121
Cryptobet(25) = 122
 
'generated with:
For X = 0 To 25
 Debug.Print "Cryptobet(" & X & ") = " & X + 97
Next X

You could also shuffle these yourself, avoiding the need to do it with a programming language.

Good luck.

thanks a bunch =)
Ill give it a try! If i get stuck i come back here =)