Help.

Hello All,
how do i put the data of an int to an edit control. i know that when i use

char *data = "Hello";

i can use

SetWindowText(editbox1, data);

but i'm having trouble putting the data of an int to the edit control. it gives me an error, cannot convert int to const char.

i have no idea how to do this, and i have looked around and gone through the help files or my borland compiler, and cannot figure this out. i'm pretty sure this is easy. but i don't know how. please help. thanx for your time.

AAG.

You need something like this:

Code:

---

#include <cstdlib>
char buffer[100];

// your other code
// blah blah blah
int data = 3;

SetWindowText(editbox1, itoa(data, buffer, 10));

---

You will get much better responses posting questions like this in the C++ forum.

Erm, well to be honest, I've never really thought about it. if it was me I would probably just make my own formatting function. You could quite easily do that. Say you have a time interval in seconds and want to display it like hh:mm:ss then you could use a function like this to return a string in that format:

Code:

---

char *formatTime(int seconds, char *buffer)
{
    int secs = seconds % 60;
    int mins = (seconds / 60) % 60;
    int hours = mins / 60;
   
    char buf[100];
    int hourlen = strlen(itoa(hours, buf, 10));
    int temp=hours;

    buffer[hourlen]=itoa(hours%10, buf, 10);
    for(int x=(hourlen-1); x>=0; x++)
    { 
          buffer[x] = (temp/10)%10;
          temp = (temp/10)%10;
    }

    buffer[hourlen+1] = ':';
    buffer[hourlen+2] = mins/10;
    buffer[hourlen+3] = mins%10;
   
    buffer[hourlen+4] = ':';
    buffer[hourlen+5] = secs/10;
    buffer[hourlen+6] = secs%10;

    buffer[hourlen+7] = '\0';

    return(buffer);
}

---

I don't guarantee that will work as it is, it's just off the top of my head. You'd have to pass it a properly allocated buffer string, that's at least long enough for the whole string plus the ening '\0' character.

Thanx, i'll try it out and play around with it, and see what i can come up with. i know its really simple in vb6. i'm pretty fluent in vb6, and have only been programming in c for a month or so. i just skimmed through the c++ console programming book and when i felt i knew enough, i jumped into win32 programming. maybe my book might have something on the subject. thanx alot for your help, i really appreciate it.
thanx again,
AAG

No problem :) I just realised at least one mistake I made, here's the corrected code:

Code:

---

char *formatTime(int seconds, char *buffer)
{
    int secs = seconds % 60;
    int mins = (seconds / 60) % 60;
    int hours = mins / 60;
   
    char buf[100];
    int hourlen = strlen(itoa(hours, buf, 10));
    int temp=hours;

    buffer[hourlen]=itoa(hours%10, buf, 10);
    for(int x=(hourlen-1); x>=0; x++)
    { 
          buffer[x] = itoa((temp/10)%10, buf, 10);
          temp = (temp/10)%10;
    }

    buffer[hourlen+1] = ':';
    buffer[hourlen+2] = itoa(mins/10, buf, 10);
    buffer[hourlen+3] = itoa(mins%10, buf, 10);
   
    buffer[hourlen+4] = ':';
    buffer[hourlen+5] = itoa(secs/10, buf, 10);
    buffer[hourlen+6] = itoa(secs%10, buf, 10);

    buffer[hourlen+7] = '\0';

    return(buffer);
}

---

The function is now painfully inefficient, but never mind, it should (might) work :)

Ok Well I Tried Your Revised Code. I got a couple of errors that i fixed by changing ':' to ":", those were the only 2 errors. then i called the function as follows

SetWindowText(edithwnd, formatTime(data, secbuffer));


all it does is exit the program when the code is run. i also set the buffer to [40]. it compiled without errors or warnings. the program opens fine. then when i hit the button that runs the code. the program exits. no error is reported, no illegal operation. it just exits as if u were to

PostQuitMessage(0);

thanx anyways
AAG.