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This is really driving me crazy, ive spent about an hour trying 2 work out whats wrong!!! And its probablyreally simple.
Basically heres the code;
Winsock1.RemoteHost = 10.0.0.2
Winsock1.RemotePort = 1985
Winsock 1.Connect
#Continued#
Any way, When run, it returns this error:
"Run Time Error 40020, Invalid Operation at current state"
The line that causes the error is;
"Winsock1.RemoteHost = 10.0.0.2"
I cant figure out why its happening!!!!!
If you can help, please reply, thanks
Hi AliBail,
It seems to me that you should use a string .
Winsock1.RemoteHost = "10.0.0.2"
What protocol are you using? TCP or UDP because there is a difference.
cheers
Ray
i thing the Winsock1 is open close it first
Winsock1.Close
Im using the TCP protocol.
I'll try closing the Winsock Connection first as well, But I think its closed anyway.
Hi AliBail,
I checked the doc files and you must use a string format
with the winsock.remotehost statement.
Thereis also a statemnet to set the protocol, but I assume that you
have it in the properties of winsock1.
[Code]
Winsock1.RemoteHost = "10.0.0.2"
This must work.
Sample of TCP Connection
1. Create a Standard EXE project
2. Change the name of the default form to frmServer
3.Change the caption of the form to "TCP Server"
4. Draw a winsock control on the form and change its name to tcpServer
5. Add two TextBox controls to the form. Name the first txtSendData, and the second txtOutput
6. Add the code below to the form
[Code]
Private Sub Form_Load()
'Set the LocalPort property to an integer
'Then invoke the Listen method
tcpServer.LocalPort = 1001
tcpServer.Listen
frmClient.Show
End Sub
Private Sub tcpServer_ConnectionRequest(Byval requestIS As Long)
'Check if the control state is closed. If not,
'close the connection before accepting new cooection.
If tcpServer.State <> sckClosed Then
tcpServer.Close
End If
' Accept the request with the requestID parameter
tcpServer.Accept requestID
End Sub
Private Sub txtSendData_Change()
'The txtBox control named txtSendData
'contains the data to be sent. Whenever the user
' types into the textBox, the string is sent
'using the SendData method.
tcpServer.SendData txtSendData.text
End Sub
Private Sub tcpServer_DataArrival(ByVal bytesTotal As Long)
'Declare a varable for the incoming data.
' Invoke the GetData method and set the Text.
'property of a textBox named txtOutput to the data.
Dim strData As String
tcpServer.GetData strData
txtOutput.Text = strData
End ub
The procedures above create a simple server application. However, to
complete the scenario, you must create a client application.
TO CREATE A TCP CLIENT
1 Add a new form to the project,and name it frmClient
2. Change the caption of the form to TCP Client
3. Add a Winsock control to the form and name it tcpClient
4. Add tow TextBox controls to frmClient. Name the first txtSend, and the second txtOutput
5. Draw a commandbutton control on the form and name it cmdConnect
6. Change the caption of the CommandButton control to Connect
7. Add the code below to the form
[Code]
Private Sub Form_Load()
' The name of the Winsock control is tcpClient
' Note: to specify a remote host, you can use
' either the IP address (ex: "121.111.1.1") or
' the computer's "friendly" name, as shown here.
'must be string type.
tcpClient.RemoteHost = "RemoteComputerName"
tcpClient.RemotePort = 1001
End Sub
Private Sub cmdConnect_Click()
'Invoke the Connect method to initiate a connection
tcpClient.Connect
End Sub
Private Sub txtSendData.Change()
tcpClient.SendData txtSend.Text
End Sub
Private Sub tcpClient_DataArrival(Byval bytesTotal As Long)
Dim strData As String
tcpClient.GetData strData
txtOutput.Text = strData
End Sub
The code above creates a simple client-server application. To try the two together
run the project, and click connect. Then type text into the txtSendData TextBox on either
form, and the same text will appear in the txtOutput TextBox on the other form.
This will set you on the way I hope.
Cheers
Ray
cheers
Ray
Thanks