Simpile Geometry/Trig

I have a right triangle in which i know sides a,b, and c:

Code:

---

            1
            /|
          / |
    a  /  |
        /    |  c
      /    |
      /      |
  2 /______ |3
          b

---

I need to find 1, 2, and 3

3 is obviously 90, and if i can find one other, i can find the third, so i was thinking about using ArcCosin. But i am new at Trig, so i'm really not sure. (This needs to be done in VB)

you don't have an arccosine in VB, but you do have an arctangent.

Tan(angle 2) = c/b

angle 2 = ATan(c/b)

Great. It works perfectly