Printable View
I understand the concept of rounding I guess, all I know is math.round(), but I need a break down of it so I can round a number like this: 14.789543 to this: 14.8 because after the 7 there is an 8, which means you would round the seven up. Can anyone tell me how this is done?
And some more detail, I need to round to the nearest tenth.
There is second optional parameter that can be sent to this function that returns it to a decimal point. So...
math.round(14.789543, 1) would return 14.8.
Thaty works somewhat, the only problem is that It's not rounding the decimal, it's rounding to the nearest whole digit.Quote:
Originally Posted by sra3cf
I need it to round to the nearest tenth.
Well are you storing the result as an Integer? Integers cannot hold Decimal places.
This is wrong:
This is more logical:vb.net Code:
Doubles are designed to perform math operations, and the Math.Round() Function returns a double.vb.net Code:
Decimal will work better than Double too...
-tg
Alright, I figured out my problem, my problem was that I was rounding a number from a textbox, so I was using CInt when I should have been using CDbl. Now can anyone tell me how to round to the nearest hundredth?
Someone already did, have you tried changing 2nd parameter of math.round at all?
Forgot about Decimal. I just usually use Double because I've never had a need to use it yet..Quote:
Originally Posted by techgnome
Before I can mark this resolved, how could I round to say, the nearest 10, like if the number is 56, it will round up to 60.
divide by 10, round, multiply by 10