SQL 2005 getting month as two digits [resolved]

Hi All,

For a quite convoluted reason I need to bulid a string which contains the month as two digits. I came up with the following sql statement

Code:

---

declare @month int
set @month = (select cast(datepart(m,getdate()) as integer))
declare @lmonth varchar(2)
set @lmonth =  CASE
        WHEN  @month <10  THEN '0' + cast(@month as varchar)
        ELSE cast(@month as varchar)
      END
select @lmonth

---

But seems to me there must be a much much sleaker way to achive the same thing, any help would be appreciated.

How about this?

Code:

---

select right('0' + cast(datepart(m,getdate()) as varchar(2)),2))

---

If that doesn't work, which database system are you using?

Thanks that does work and cuts down on the code quite considerably.

As you now have it sorted out, could you please do us a little favour, and mark the thread as Resolved?
(this saves time reading for those of us who like to answer questions, and also helps those who search to find answers)

You can do it by clicking on "Thread tools" just above the first post in this thread, then "Mark thread resolved". (like various other features of this site, you need JavaScript enabled in your browser for this to work).


edit: sorry, I see you've done it manually (but with Resolved at the end of the thread title rather than the start)

Have learnt something else now, didn't realise you could resolve a thread automatically using thread tools. Will remember for next time.
Thanks