[RESOLVED] Customer Registeration problem

Hi,

I am using the code below to try and send a customers information from a flash form to a database. However, when I check the database no information has been added. I am not very good at php!

Code:

---

<?php
// Database connection variables
$dbDatabase = "Bazaar Ceramics";
//convert the POST variables from flash to local variables
$cid = $_POST['cid'];
$FName = $_POST['fname'];
$LName = $_POST['lname'];
$Email = $_POST['email'];
$SNum = $_POST['snum'];
$SName = $_POST['sname'];
$Suburb = $_POST['suburb'];
$PCode = $_POST['pcode'];
$Country = $_POST['country'];
$Phone = $_POST['phone'];
$User = $_POST['user'];
$Password = $_POST['upassword'];

// Make sure the data has been sent to the script from flash
if($cid==""||$LName ==""){
echo '&message=you+must+enter+customer+record&';
exit;
}
//check if you can connect to the mysql db otherwise exit
$conn = @mysql_connect("localhost", "admin", "");
if (!$conn) {
die("Connection failed: " .mysql_error());
}
//connect to database or exit
if (!(mysql_select_db($dbDatabase, $conn))){
echo '&message=db+selection+failed&';
exit;
}
//send mysql a query to select records from the products table where the id's match. If the query fails exit
if (!($result = mysql_query("SELECT * FROM customers where customerid= '$cid'"))){
echo '&message=query+failed&';
exit;
}
//Retrieve the number of rows (records)that have been returned from above query
$num_results = mysql_num_rows($result);
if($num_results <= 0) {//customer does not exist so insert
$query = "INSERT INTO customers (cid, FName, LName, Email, Housenum,  Streetname, Suburb, Postcode, Country, Phone, Username, Password)
VALUES ('$cid','$FName', '$LName', '$Email', '$SNum', '$SName','$Suburb','$PCode','$Country','$Phone','$User','$Password')";
if (mysql_query($insert, $conn))
echo "&message=the+customer+'$FName'+'$LName'+has+been+successfully+added&";
else
echo '&message=the+insert+was+not+successful&';
}else { //customer exists so update existing customer
$update = "update products set FName='$FName'; LName='$LName'; where customerid='$cid'";
if(mysql_query($update, $conn))
echo "&message=the+details+have+been+updated&";
else
echo "&message=update+not+successful&";
}
?>

---

Flash code:

Code:

---

                                var Dataloader:URLLoader = new URLLoader();
var variables:URLVariables = new URLVariables();

this["btnSubmit"].addEventListener(MouseEvent.CLICK, sendData);

function sendData(event:MouseEvent):void {
var url:String = "C:/phpdev/www/flash/dynamicWebsite/customerUpdate.php";
var req:URLRequest = new URLRequest(url);
req.method = URLRequestMethod.POST;
req.data = variables;
                variables.cid = tiCustomerID.text;
                variables.fname = txtFName.text;
                variables.lname  = txtLName.text;
                variables.email = txtEmail.text;
                variables.snum = txtSNum.text;
                variables.sname = txtSName.text;
                variables.suburb = txtSuburb.text;
                variables.pcode = txtPCode.text;
                variables.country = txtCountry.text;
                variables.phone = txtPhone.text;
                variables.user = txtUser.text;
                variables.upassword = txtPassword.text;
                //Send data to php script
                Dataloader.load(req);
}

---

Thanks,

Nightwalker

My first guess at your problem is right here:

Code:

---

var url:String = "C:/phpdev/www/flash/dynamicWebsite/customerUpdate.php";

---

How are you testing your SWF? Previewing through Flash? Because you're accessing this file through C:/, it likely isn't getting processed as PHP. Change your file path to a relative one, then access your SWF file through a browser, on http://localhost or however you have your local development server set up.

You could confirm this by putting a text box on your stage, naming it "myText," and adding this to your AS:

Code:

---

...
Dataloader.load(req);
Dataloader.addEventListener(Event.COMPLETE, loaderCompleteHandler);
}

function loaderCompleteHandler(event:Event):void {
        myText.text =Dataloader.data;
}

---

If the text box populates with the text of the PHP file ("<?php ..."), it's not being processed.

Hi SambaNeko,

I changed the url to the above because when I tested the script with url:

Code:

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var url:String = "http://localhost/flash/dynamicWebsite/customerUpdate.php";

---

because I also had the same problem above using this url! Yeah, I was testing the string data with:

Code:

---

    trace (req.data);

---

Placed after Dataloader.load (req); in the above code! However, that only returned the string being sent.

Edit:

I just tried your suggestion above and it confirms that the data is being sent to the script!

I think the problem with the php lies in the local variables:

Code:

---

//convert the POST variables from flash to local variables
$cid = $_POST['cid'];
$FName = $_POST['fname'];
$LName = $_POST['lname'];
$Email = $_POST['email'];
$SNum = $_POST['snum'];
$SName = $_POST['sname'];
$Suburb = $_POST['suburb'];
$PCode = $_POST['pcode'];
$Country = $_POST['country'];
$Phone = $_POST['phone'];
$User = $_POST['user'];
$Password = $_POST['upassword'];

---

As soon as a check such as:

Code:

---

// Make sure the data has been sent to the script from flash
if($cid==""||$LName ==""){
echo '&message=you+must+enter+customer+record&';
exit;
}

---

is preformed the echo message is triggered confirming that no data is being received by the script. Have tried changing the position of the data in the string being sent to match up with the position of the form, however, it didn't solve the problem.

You're passing $insert but it should be $query in if (mysql_query($insert, $conn))

Merri's right about the above, but if you're not getting passed the variable check, then your script hasn't gotten to that problem yet.

I've tried replicating your script in Flash, and my PHP is receiving the variables properly. Have you tested that the variables are populated in Flash before sending them to PHP? Try adding this after you've set all those variables:

Code:

---

trace(variables.toString());

---

That'll spit out a long string of all your variable keys and values. See what it gives you...

Quote:

---

Originally Posted by Merri

You're passing $insert but it should be $query in if (mysql_query($insert, $conn))

---

Thanks! That was the problem, the data gets submitted to the database now.

Quote:

---

Originally Posted by SambaNeko

Merri's right about the above, but if you're not getting passed the variable check, then your script hasn't gotten to that problem yet.

I've tried replicating your script in Flash, and my PHP is receiving the variables properly. Have you tested that the variables are populated in Flash before sending them to PHP? Try adding this after you've set all those variables:

Code:

---

trace(variables.toString());

---

That'll spit out a long string of all your variable keys and values. See what it gives you...

---

Thanks! Trace statement proved useful in showing the php in the flash environment.

Edit:

Is there a way to combine the following two functions into one so that data gets submitted the script does not override the database if it already exist but creates it if it doesn't exist?

Code:

---

//drop database
$query = "DROP database if exists BazaarCeramics";
if (mysql_query($query, $conn)) {
echo ("Database drop query successful");
}else {
die ("Database query failed: " .mysql_error());
}

//create database
$query = "CREATE database BazaarCeramics";
if (mysql_query($query, $conn)) {
echo ("Database create query successful");
}else {
die ("Database query failed: " .mysql_error());
}

---

Quote:

---

Is there a way to combine the following two functions into one so that data gets submitted the script does not override the database if it already exist but creates it if it doesn't exist?

---

Yes, use this query: "CREATE DATABASE IF NOT EXISTS BazaarCeramics".

Quote:

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Originally Posted by SambaNeko

Yes, use this query: "CREATE DATABASE IF NOT EXISTS BazaarCeramics".

---

Thanks!

I changed the functions before and after the create tables function like so:

Before:

Code:

---

//create database
$query = "CREATE DATABASE IF NOT EXISTS BazaarCeramics";
if (mysql_query($query, $conn)) {
echo ("Database create query successful");
}
//select database
if (mysql_select_db("BazaarCeramics", $conn)) {
echo ("Database selection successful");
}else {
die ("Could not locate BazaarCeramics database" .mysql_error());
}

---

After:

Code:

---

if (mysql_query($query, $conn)) {
echo ("table users query successful");
}else {
//connect to database or exit
if (!(mysql_select_db($dbDatabase, $conn))){
echo '&message=db+selection+failed&';
exit;
}
}

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