Password Input "*"

How to make the input by the user to appear as "*" and not the actual letters (it is a password input). And how to read the entered value.
Note: This is a 16 bit DOS application.

Thanks!!

I don't have a 16-bit compiler so I can't code anything up, but what about just hooking the keyboard?

I never programmed in 16 bit enviroments (DOS). SO could you explain how to hook the keyboard.

I wrote this for a password program.

Code:

---

void GetPass(char *input, int length, char output)
{
        char temp;
        for(int i = 0; i < length;)
        {
                temp = getch();
                if(temp == 13 && i > 0)
                {
                        input[i] = 0;
                        break;
                }

                if(i > 0)
                {
                        if(temp == 8)
                        {
                                putchar(8);
                                putchar(' ');
                                putchar(8);
                                input[--i] = 0;
                        }
                }

                if(temp != 8 && temp != 13)
                {
                        putchar(output);
                        input[i] = temp;
                        i++;
                }
        }
}

---

Vlatko, where did you get your 16b DOS compiler? I would be very interested in it.

Thanks Chimpface i'll give it a try.

The compiler is Turbo C++ 3.0. I have it on a CD i bought yesterday along with other 16 and 32 bit compilers.

I would send it but i am on 33600bps and the TC++ 3.0 is 12MB so..

TC3 is 16b?

Cool, I've got that :D