[RESOLVED] 3 label 9 condition?

How to...

i have 3 label and i want to combine all possible combinations wath is the right way?

the condition is:

1°) all label have caption =blank or empty
2°) labe1 caption is filled label2 caption is filled label3 caption is no blank
3°) label1 caption is balnk label2 caption ecc...
...
9°)...

i think the combination are 9 (3*3) or not?

case selcet? or...

If each Caption is to be separated by a single space this statement is all you need.

str = Trim$(Trim$(Trim$(Label1.Caption) & " " & Trim$(Label2.Caption)) & " " & Trim$(Label3.Caption))

No you have 8 combinations. A label is either empty or not so it only have two states and you have 3 labels which gives 2^3 = 8 combinations.

If you don't care what the text in the labels read but only want to check if the Caption is empty or not you can convert these states into numbers from 0 to 7.
0 = All three labels are blank
1 = Label1 contains text, the others are empty.
2 = Label2 contains text, the others are empty.
3 = Label1 and Label2 contains text while Label3 is empty.
4 = Label3 contains text, the others are empty.
5 = Label3 and Label1 contains text while Label2 is empty.
6 = Label3 and Label2 contains text while Label1 is empty.
7 = All labels contains text.

You can easily get these numbers by saying that Label1 have the value 1 if it contains text, Label2 have the value 2, while Label3 have the value 4 (binary). If a label doesn't contain text it has the value 0.

Code:

---

Dim value As Integer
value = IIf(Label1.Caption <> "", 1, 0)
value = value + IIf(Label2.Caption <> "", 2, 0)
value = value + IIf(Label3.Caption <> "", 4, 0)

---

Using the code above "value" will be something between 0 and 7. Now use a Select Case and do whatever.

Joacim

Very nicely presented (the cases 0 - 7) :thumb:

Spoo