[3.0/LINQ] Text to ascii binary

Im trying convert a text string to ascii binary

such as A =01000001
test =01110100011001010111001101110100

here is an example
http://www.roubaixinteractive.com/Pl...ry_To_Text.asp


I understand that im goign to have to do a for each loop for each char C in string x

but im not sure how to get the binary ascii char out of it


i know this is probably pretty simple but im just drawing a blank

Code:

---

string Int2Bin(int c)
        {
            string ret = "";
            while (c > 0)
            {
                ret = (((c & 1) != 0) ? "1" : "0") + ret;
                c >>= 1;
            }
            return ret.PadLeft(8,'0');
        }
        string Str2Bin(string str)
        {
            string ret = "";
            if (str.Length > 0)
            {
                ret = Int2Bin(str[0]);
                for (int i = 1; i < str.Length; i++)
                {
                    ret += " " + Int2Bin(str[i]);
                }
            }
            return ret;
        }

---

this is pretty close but something is off im looking into it now

"Robert"
website =010100100110111101100010011001010111001001110100
Program=001001010111101100100011010100110010011100010111

a=01000011
a=01100001

Its backwards

updated, my bad :P. Was appending on the wrong side.

Even though High's code probably works, I think this is more readable:

Code:

---

        private void button1_Click(object sender, EventArgs e)
        {
            MessageBox.Show(ConvertToBin("test"));

        }

        string ConvertToBin(string s)
        {
            StringBuilder sb = new StringBuilder();
            Byte[] bytes= System.Text.Encoding.ASCII.GetBytes(s);
            foreach (byte b in bytes )
                sb.Append(Convert.ToString(b,2).PadLeft(8,'0'));
            return sb.ToString();
        }

---

Quote:

---

Originally Posted by high6

Code:

---

string Int2Bin(int c)
        {
            string ret = "";
            while (c > 0)
            {
                ret = (((c & 1) != 0) ? "1" : "0") + ret;  <------Here
                c >>= 1;
            }
            return ret.PadLeft(8,'0');
        }
        string Str2Bin(string str)
        {
            string ret = "";
            if (str.Length > 0)
            {
                ret = Int2Bin(str[0]);
                for (int i = 1; i < str.Length; i++)
                {
                    ret += " " + Int2Bin(str[i]);
                }
            }
            return ret;
        }

---

---

I figured it out too. I am intrigued by this line ( marked HERE)

ive never seen that type of syntax could you explain it a little better

sorry to be going the long way around this


but I want to convert the binary string to a Dec number

I tried this code
return Convert.ToInt64(sb.ToString(), 2);

and it works till i get up into the words that are 8 or 9 letters long
then i get a stack overflow.

i dont see a convert.tolong what should i use

Quote:

---

Originally Posted by Crash893

I figured it out too. I am intrigued by this line ( marked HERE)

ive never seen that type of syntax could you explain it a little better

---

Code:

---

ret = (((c & 1) != 0) ? "1" : "0") + ret;

---

It is called a condition operator.

It is basically like doing.

Code:

---

if ((c & 1) != 0)
{
    ret = "1" + ret;
}
else
{
    ret = "0" + ret;
}

---

Quote:

---

Originally Posted by Crash893

sorry to be going the long way around this


but I want to convert the binary string to a Dec number

I tried this code
return Convert.ToInt64(sb.ToString(), 2);

and it works till i get up into the words that are 8 or 9 letters long
then i get a stack overflow.

i dont see a convert.tolong what should i use

---

Long/Int64 are the same, they both can only store 8 bytes(64 bits). So you cannot store a string longer then 8 bytes in an Int64.