[RESOLVED] Binary file in table, problem With adding Row

Hello all,

I have code in Word macro which is reading file from the disk and converting it to binary. This binary should be inserted in the internal table (Dim As object) for further posting.

Here is the code:

Code:

---

Sub Read_File(FileNameFull As String)
    Dim oBinaryDataTab As Object
    Dim oBinaryDataRow As Object
    Dim lBytesToRead As Long
    Dim iNumChars, i As Integer
    Dim s1022, s2044, sX As String
    Dim fs, f, ts As Object
    Dim ReadFile As String

' Actually does the work of uploading the document in 1022 byte pieces.
    ReadFile = 0
    Set fs = CreateObject("Scripting.FileSystemObject")
    Set f = fs.GetFile(FileNameFull)
    Set ts = f.OpenAsTextStream(1, -2)
    lBytesToRead = f.Size
    ReadFile = f.Size
    Do While ts.AtEndOfStream <> True
        If lBytesToRead < 1022 Then
            iNumChars = lBytesToRead
        Else
            iNumChars = 1022
        End If
        s1022 = ts.Read(iNumChars)
        s2044 = ""
        For i = 1 To Len(s1022)
            sX = Hex$(CByte(Asc(Mid(s1022, i, 1))))
            If Len(sX) = 1 Then
                sX = "0" + sX
            End If
            s2044 = s2044 + sX
        Next i
        Set oBinaryDataRow = oBinaryDataTab.Rows.Add
        oBinaryDataRow("LINE") = s2044
        lBytesToRead = lBytesToRead - iNumChars
    Loop
       
End Sub

---

But on the row "Set oBinaryDataRow = oBinaryDataTab.Rows.Add" code just stopped to work.
Can somebody give me a hint how to proceed?
I also tried to Dim oBinaryDataTable As Table and oBinaryDataRow as Row with the same result.

TIA

Gordan

An object in VBA is much like a variant in being that it represents and can store any data type that is of the type "object." That was a mouthful and probably not the best way to explain it. In essence an Object by itself is Nothing and can do nothing for you without first being assigned.

You can't do this:

Code:

---

oBinaryDataTab.Rows.Add

---

until you assign oBinaryDataTab with an object that supports the Rows.Add method. My question to you is what type of object is this data tab supposed to be?

Hello,

it should be table with single column, and n rows.

Gordan

I understand you want it to be a table, but what type of object are you wanting to represent this table as? Your choices are things like arrays, excel spreadsheets, database tables, or anything like that.

Hello,

sorry, this is an array.
Problem is that system which will receive data can accept this only as internal table. In it one row is interpreted as "Uninterpreted sequence of bytes".

Gordan

you need to set oBinaryDataTab to be a table in your word document, at least i think that is what you want to do, otherwise you are not keeping the data anywhere, that i can see
maybe
set oBinaryDataTab = activedocument.tables.add 'with parameters for single column and row, headers etc

It's an array, westconn.

You manage array dimensions like this.

Code:

---

Dim arr() as string 'declare uninitialized array
ReDim arr(0) as string 'init array to 1 dimensions
arr(0) = "text"
ReDim Preserve arr(1) as string 'preserve the old values in the array
arr(1) = "new text"
Debug.Print arr(0), arr(1)

---

i saw that he said that, but

Quote:

---

This binary should be inserted in the internal table (Dim As object)

---

and oBinaryDataTab has some properties that look like a table

Hello all,

thank you for all of your responses.

To clarify some things, oBinaryDataTab is internal table which is not represented in word as text. Content of the table is not visible to word user. This "table" is needed to send content of the file from file system in another program.

Because file is bigger (longer) than s1022 string it must be put in internal table with one column named "LINE". Number of rows is dynamic and depend on length of file on the disk.

When received in another system this table will be represented as "Uninterpreted sequence of bytes".

This code was OK before
Set oBinaryDataRow = oBinaryDataTab.Rows.Add
oBinaryDataRow("LINE") = s2044
When both oBinaryDataTab and Row were defined as Objects.

Now through debug mode I can see only that word is stopping on the first line without any error message.

Appreciated any response,

Gordan

No one can understand what is "internal table".
With your code in post#1:

with just
Dim oBinaryDataTab As Object
you cannot use
Set oBinaryDataRow = .Rows.Add
oBinaryDataRow("LINE") = s2044
if before that you do not have a line that similar to this:
Set oBinaryDataTab = ... '-- whatever you call "internal table"

you can add a row to a table, once the table has been set to the object, but the "Line" item (probably named range or bookmark) will also not exist unless added in code and may be a read only property

either you have copied some incomplete code or the items were set in some other part of the code
or your instructions are not complete

Hello all,

again thank you very much for helping me. You all understand that I am not very familiar with VBA, but some big german ERP company which has declarations not familiar in outher world :)

anhn was right, set oBinaryDataTab = "table", was missing. After I defined this it started to work, but... :)

this part of the code
Set oBinaryDataRow = oBinaryDataTab.Rows.Add
oBinaryDataRow("LINE") = s2044

as I understand it should be doing following:
1. add row (oBinaryDataRow) to table (oBinaryDataTab)
2. fill new row with value in s2044.

As you can see this two lines of the code are in loop, so until there is nothing in s2044, new row sould be added to table and value in s2044 added to it.

Am I right or something is missing because oBinaryDataTab is empty even in the first pass.

TIA

Gordan

P.S. I will reward anhn post as soon as I discover how :)

yes but as i indicated before "LINE" must be a valid item property name of the table, is it adding a new row each time it loops, but not filling it?i am also not sure what table (word or other) you are using
if it is a word table try like

vb Code:

Set oBinaryDataRow = oBinaryDataTab.Rows.Add
oBinaryDataRow.cells(1) = s2044

Hello,

thank you all on received responses. all of them helped me to learn something new, and on the end I achieved result that I expected.

There were some other errors in String (s2044) definition but I resolved it and whole function is OK.

Best regards,

Gordan