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In math class I came up with a theory for an equasion like:
ax^2 + bx + c = 0
If thought that if b-a=c Then
the discriminant (b^2-4ac) = (a-c)^2
I think this always works. Please correct me if I'm wrong.
Also,
If b-a=c Then the solutions are
-c and c-b
That one I am very unsure because it only sometimes works. If you can come up for something like this, please tell me.
-mark
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???
if c = b - a then (B^2 - 4*a*c) = B^2 -4*a*(b-a)
With a little work you get B^2 - 4*a*b + 4*a^2
This is (b - 2*a)^2
This leads to the following.
X = [-b + (b - 2*a) ] / 2*a
X = [-b - (b - 2*a) ] / 2*a
X = -1
X = (a - b)/a
The above is the correct result for c = (b - a)
I do not know what you want to do next.
