[RESOLVED] Algebra with triangle sides etc. Im stumped.

Hey there. My skill in the area of math has faded fast over the recent years, and now I find myself completely stuck with this problem:
I know the hypotenuse of a triangle. I need to find the length of the other 2 sides of this triangle. The only thing I know about the other 2 sides is their "ratio".

Basically pythagoras:
A^2 + B^2 = C^2
Where C is known. And I also know X in this equation:
A / X = B.

This led me to simplify the equation into:
A^2 + (A / X)^2 = C^2

But thats as far as I got :blush:

I'd really appreciate some help!

you're almost there: factor out A^2 giving

A^2 (1 + 1/X^2) = C^2

A^2 = C^2/(1 + 1/X^2)


A = C / SQRT(1 + 1/X^2)

Wonderful! Thank you very very much :)