[RESOLVED] [2005] Open File dialog error?

Hi.. I'm having problem with open file dialog

When I first open the program then select(browse) the files, if I press the cancel button, the entry files are not selected(not go to the data grid), but after the first try, if I cancel, the entry from the first try got inserted, Is this bug? I've used filedialog.dispose().. :(
I've tried to put the dispose after showdialog() but it still doesn't work..

here's the code

Code:

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        FileDialog.ShowDialog()

        total = FileDialog.FileNames.Length
        uplot = New String(total) {}
        If total > 0 Then
            dgv_uplot.Rows.Add(total)
        End If

        FileDialog.Dispose()

        For i = 0 To total - 1
            uplot(i) = Me.filedialog.FileNames(i).ToString

            dgv_uplot.Item(1, baris).Value = uplot(i)
            baris += 1
        Next

        FileDialog.Dispose()

---

The code inside if statement will get executed only if the user selected a file and presses ok .

Code:

---

If FileDialog.ShowDialog() = DialogResult.OK Then

        total = FileDialog.FileNames.Length
        uplot = New String(total) {}
        If total > 0 Then
            dgv_uplot.Rows.Add(total)
       
        For i = 0 To total - 1
            uplot(i) = Me.filedialog.FileNames(i).ToString

            dgv_uplot.Item(1, baris).Value = uplot(i)
            baris += 1
        Next

End If

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Quote:

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Originally Posted by Pirate

The code inside if statement will get executed only if the user selected a file and presses ok .

Code:

---

If FileDialog.ShowDialog() = DialogResult.OK Then

        total = FileDialog.FileNames.Length
        uplot = New String(total) {}
        If total > 0 Then
            dgv_uplot.Rows.Add(total)
       
        For i = 0 To total - 1
            uplot(i) = Me.filedialog.FileNames(i).ToString

            dgv_uplot.Item(1, baris).Value = uplot(i)
            baris += 1
        Next

End If

---

---

Thanks.. It's working now :D :D