[RESOLVED] [2005] TableLayoutPanel

I have a tablelayoutpanel set to 1 row that is loaded with a picture box in each colum. How can I tell when one of the picture boxes has been clicked on?

the pictureboxes are the same in a tablelayoutpanel as they are on a form, so you can use the picturebox_click event

Ok that may help some but these picture boxes are created at runtime so how would I know how to build a click event then?

you need to use addhandler to specify a handler.
try this. it adds a picturebox to your form each time you click the button.
pictureboxes_click handles the click event of your dynamic pictureboxes.

vb Code:

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
    Static index As Integer = 0
    Dim pb As New PictureBox
    pb.BackColor = Color.Red
    pb.Left = pb.Width * index
    pb.Tag = index
    index += 1
 
    Me.Controls.Add(pb)
    AddHandler pb.Click, AddressOf pictureboxes_click
End Sub
 
Private Sub pictureboxes_click(ByVal sender As Object, ByVal e As System.EventArgs)
    MsgBox(DirectCast(sender, PictureBox).Tag)
End Sub

great example and gave me an idea. This is what i tried:

Code:

---

Private Sub pbselect()
        MsgBox("It worked George")
    End Sub


    Private Sub getpics()
       
        Debug.WriteLine(totalpic)
        For count As Integer = 0 To totalpic - 1
            pb(count) = New PictureBox
            Controls.Add(pb(count))
            With pb(count)
                .Image = pics(count)
                .Width = 100
                .Height = 75
                .Visible = True
                .SizeMode = PictureBoxSizeMode.StretchImage
                AddHandler .Click, AddressOf pbselect
            End With

        Next



    End Sub

---

But i get an error saying:
does not have the same signiture as deligated

you should have a handler sub:

vb Code:

Private Sub pbselect(ByVal sender As Object, ByVal e As System.EventArgs) 
    'your code
end sub

That worked GREAT thanks a bunch :)