[RESOLVED] winform OpenFileDialog

Hello,
The following code shows how to use the openFileDialog to read the contents of a .csv file into a textbox.

Question:
After selecting the file iin the dialog, how do I actually open the file?
remember that I would like to open the .csv file and NOT read it into the textbox.

Dim ts as StreamReader
openFileDialog1.CheckFileExists = true
openFileDialog1.CheckPathExists = true
openFileDialog1.DefaultExt = "csv"

openFileDialog1.Filter = "Text files (*.csv)|*.csv|" + "All files|*.*"
openFileDialog1.Multiselect = false
openFileDialog1.FilterIndex = 2
openFileDialog1.ValidateNames = true

if (openFileDialog1.ShowDialog() = DialogResult.OK)

ts = StreamReader(openFileDialog1.OpenFile())

txtSQL.Text = ts.ReadToEnd()
end if

Thanks

Just use the Process.Start method

Process.start(openFileDialog1.FileName)

This open the file in default editor :)

More info : http://msdn.microsoft.com/en-us/libr...50(VS.71).aspx

Hope this helps

Dana

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Have got your answer ?

vb Code:

Me.OpenFileDialog1.Filter = "All Microsoft CSV Files|*.csv"
 Me.OpenFileDialog1.Title = "Select the CSV Document to Open"
 Me.OpenFileDialog1.FileName = ""
 If OpenFileDialog1.ShowDialog = DialogResult.OK Then
    If IO.Path.GetExtension(OpenFileDialog1.FileName) = ".CSV" Then
        Me.OpenFileDialog1.Dispose()
        Me.SendToBack()
        System.Diagnostics.Process.Start(OpenFileDialog1.FileName)
    End If
 End If

Yes, I have the answer.
Many thanks