[RESOLVED] Search Database and display the whole row

Hello

I'd like to know how can i search the database and display the whole row

i mean like i have a table called family it has fields ( ID "primary key",FirstName,LastName,Age)

i want to search the FirstName Field for john and display the FirstName and LastName and Age of each search result found in the FirstName Field

How can i do this in PHP?

I am sorry but i am a bit noew to mysql and i want to learn more :)

Thanks
Cheers

well you can use SELECT:

PHP Code:

---

$sql = "SELECT * FROM `family` WHERE FirstName='john' LIMIT 1";
$query = mysql_query($sql);
$result =  mysql_fetch_array($query);

echo "First Name: " . $result['FirstName'] . "<br>";
echo "Last Name: " . $result['LastName'] . "<br>";
echo "Age: " . $result['Age'] . "<br"; 


---

That will select the first row with the name "john" in the database and display the info.

If you want to search the db, and display all the results you can do this:

PHP Code:

---

$sql = "SELECT * FROM `family` WHERE FirstName LIKE '%john%' LIMIT 1";
$query = mysql_query($sql);

while($result =  mysql_fetch_array($query)) {
     echo "ID: " . $result['ID'] . "<br>";
     echo "First Name: " . $result['FirstName'] . "<br>";
     echo "Last Name: " . $result['LastName'] . "<br>";
     echo "Age: " . $result['Age'] . "<br><hr>";
} 


---

There is a link in my signature with MySQL/PHP examples as well

Actually dclamp, he wants to search for every record with the first name of john so drop off the LIMIT 1.
Also when you do pattern matching you use LIKE not =
http://dev.mysql.com/doc/refman/5.0/...-matching.html

So....
SELECT * FROM `family` WHERE FirstName LIKE '%john%'

Thanks Guys for your replies

but i'd like to know what does $result represent i mean does it represent an array for only 1 result? and how can i echo the other results?

Thanks again
Adel

dclcamps post gives examples of both :D

Quote:

---

Originally Posted by lordadel

Thanks Guys for your replies

but i'd like to know what does $result represent i mean does it represent an array for only 1 result? and how can i echo the other results?

Thanks again
Adel

---

Yes $result is 1 record, this is why you loop through all of the records using while.

Quote:

---

Originally Posted by k1ll3rdr4g0n

Actually dclamp, he wants to search for every record with the first name of john so drop off the LIMIT 1.
Also when you do pattern matching you use LIKE not =
http://dev.mysql.com/doc/refman/5.0/...-matching.html

So....
SELECT * FROM `family` WHERE FirstName LIKE '%john%'

---

ah i knew that. i just copied and pasted the top code and edited a little for the bottom example

changed :)

dclamp's variable names are misleading. At the least, $query should be $resultset and $result should be $row. However, you should give them more descriptive names than that.

If you need more advanced pattern matching than the LIKE operator you can also use the REGEXP operator. If you need to search large text fields you can use full-text search.

Thanks Guys :)
rep given :)