Help Me - Scalar Variable

I have this program but when i debug i, dont know what the error is.

What im trying to do here is to pass a data from a Form(MainMenu) to a class(tableClass) to be process. From the MainMenu i assign Cust_table with 1, thats the integer shall be pass to tableClass.

Code:

---

Dim Cust_table As New TableClass
        Cust_table.Table_No = 1

---

Upon receiving data from MainMenu form. If u can see, the blue code part
is working fine. But when it comes to If, else. It have this error


Must declare the scalar variable "@Cust_table".



TableClass code

Code:

---




Get
            Return Cust_table
        End Get
        Set(ByVal value)
            Cust_table = value

Dim Conn As New SqlConnection("Data Source=ANNAS;Initial Catalog=RMS01;Integrated Security=True")

Dim command As New SqlCommand("SELECT Counter FROM CounterMeja WHERE Meja = @Cust_table", Conn)

            Conn.Open()
            command.Parameters.AddWithValue("Cust_table", Cust_table)
            command.ExecuteScalar()


            If Counter = 0 Then

                Dim command2 As New SqlCommand("Update CounterMeja Set
                Counter = 1 Where Meja = @Cust_table", Conn)
                Command.Parameters.AddWithValue("Cust_table", Cust_table)
                command2.ExecuteNonQuery()
                OrderForm.Show()
            Else
                Dim Result As String
                Result = ("Sorry this table has already been occupied")
            End If

            Conn.Close()

---

My second question is, why can't i use CustTable in first part not the second part. Eventh thought it already been assign the parameter pass right.

thank U

change

vb Code:

commad.Parameter.addWithValue("Cust_Table", Cust_Table)

to

vb Code:

commad.Parameter.addWithValue("@Cust_Table", Cust_Table)

They are two different commands.... the first one you add the parameter to... which is good... but on the second one, you've used Command again instead of Command2.... so it's never adding the parameter to your second command, it just simply added it again to the second one.

-tg