[RESOLVED] [2008] Almost Infinite Loop
pfffffffftttttttttttt i waited 1 whole hour before giving up
this loop is almost infinite
i got this code...
Code:
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
'n → n/2 (n is even)
'n → 3n + 1 (n is odd)
Dim n As Long, ChainLength As Integer, LargestChain As Integer
LargestChain = 0
For n = 1 To 1000000
ChainLength = 0
Do Until n = 1
If n Mod 2 = 0 Then
n = n / 2
ChainLength = ChainLength + 1
Else
n = 3 * n + 1
ChainLength = ChainLength + 1
End If
Loop
If ChainLength > LargestChain Then LargestChain = ChainLength
Next
TextBox1.Text = LargestChain
TextBox2.Text = n
End Sub
The question is the following:
Quote:
The following iterative sequence is defined for the set of positive integers:
n → n/2 (n is even)
n → 3n + 1 (n is odd)
Using the rule above and starting with 13, we generate the following sequence:
13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1
It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. Although it has not been proved yet (Collatz Problem), it is thought that all starting numbers finish at 1.
Which starting number, under one million, produces the longest chain?
NOTE: Once the chain starts the terms are allowed to go above one million.
Re: [2008] Almost Infinite Loop
Here's the main problem.
You're using n in your for loop. Then in the do loop, you're changing the value of n. The first time through, n=1, so it ignores the do loop and moves on. The next time through, n=2, so n is divided by 2, which makes n=1 and it moves on through the for loop, which makes n=2, so it's divided by 2, which makes n=1 and it moves on through the for loop, which makes n=2, so it's divided by 2, which makes n=1. Continue that forever.
This is actually an infinite loop, there's no almost about it. You're never actually doing any of the processing that you want.
Re: [2008] Almost Infinite Loop
Try this instead:
Code:
Dim bNum As Long = 0
Dim bMaxNum As Long = 0
Dim n As Long, ChainLength As Integer, LargestChain As Integer
LargestChain = 0
For n = 1 To 1000000
ChainLength = 0
bNum = n
Do Until bNum = 1
If bNum Mod 2 = 0 Then
bNum = bNum / 2
ChainLength = ChainLength + 1
Else
bNum = 3 * bNum + 1
ChainLength = ChainLength + 1
End If
Loop
If ChainLength > LargestChain Then
LargestChain = ChainLength
bMaxNum = n
End If
Next
According to my test, the number is 837,799 and it produces a chain that's 524 numbers long.
Re: [2008] Almost Infinite Loop
your answer is correct
thx