Date issue

Hai friends,

i just want to calculate employee work hours.
i use the following method and work well it seems.
is this method i am using is professional php way? if not, please tell what type of problem can be occour?

example :

Code:

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$timein=09:10:00;
$timeout=22:20:00;
$workhrs=$timeout-$timein;

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I don't know what PHP version you're using, but that code is invalid.
There is no date literal syntax.

This'll work in most newer versions:

PHP Code:

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$timein = strtotime('09:10:00');
$timeout = strtotime('22:20:00');

$workhrs = strftime('%I:%M:%S', $timeout - $timein);

echo $workhrs; 


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Note that PHP versions 5.1.0 and above running in strict standards mode will throw a warning if no default time zone is set before using any of the date/time functions. You can set this in php.ini, or using the date_default_timezone_set function.

Quote:

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Originally Posted by penagate

I don't know what PHP version you're using, but that code is invalid.
There is no date literal syntax.

This'll work in most newer versions:

PHP Code:

---

$timein = strtotime('09:10:00');
$timeout = strtotime('22:20:00');

$workhrs = strftime('%I:%M:%S', $timeout - $timein);

echo $workhrs; 


---

Note that PHP versions 5.1.0 and above running in strict standards mode will throw a warning if no default time zone is set before using any of the date/time functions. You can set this in php.ini, or using the date_default_timezone_set function.

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Pana, thanks for the codes. before i try it,
actually my php version is 4.4.4
my date substraction code in the first post really works :)
i dont no y.

ill try your code. it seems the professinal method.

I didn't know it worked in 4.4. I tried it in 6 and it didn't, so it's probably deprecated and should be avoided.

ok :)

pana
in

Code:

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$workhrs = strftime('%I:%M:%S', $timeout - $timein);

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what is '%I:%M:%S' tells? what is the usage of % sign in php?

please.

They're listed here:
http://php.net/manual/en/function.strftime

strftime(), yes now i undestood pana,
i ll come back.

pana, i have some problem with your code. it shows invalid tot hours.

time_in | time_out | total_hours
08:00:00 | 16:00:00 | 3

Code:

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$temp_time_in=strtotime($timein);
$temp_time_out=strtotime($timeout);
//calculate total hours of work
$tothr = strftime('%I', $temp_time_out - $temp_time_in);

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