[RESOLVED] Opening VB .NET application from other VB .NET application

Hello,

I would like to open VB .NET application from other VB .NET application by clicking form button.
This is the code that I use:

Code:

---

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
        If IO.File.Exists("c:\Documents and Settings\User\My Documents\Visual Studio 2005\Projects\My Application\My Application\bin\Debug\My Application.exe") Then
            System.Diagnostics.Process.Start("c:\Documents and Settings\User\My Documents\Visual Studio 2005\Projects\My Application\My Application\bin\Debug\My Application.exe")

Else
            MsgBox("My Application.exe file was not found")
End If
    End Sub

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After clicking the button, "My Application" start form opens, but it has very limited functionality – some forms inside the application can’t be opened.

If I open My Application.exe in a normal way (through Windows Explorer), it works fine.

May be I am using wrong command to open application?

In this case you must also set the directory from which the process starts. I don't know when exactly this is needed but I guess it has something to do with multifile applications.

Code:

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        If IO.File.Exists("c:\Documents and Settings\User\My Documents\Visual Studio 2005\Projects\My Application\My Application\bin\Debug\My Application.exe") Then

            Dim myProcess As New Process

            myProcess.StartInfo.FileName = ("c:\Documents and Settings\User\My Documents\Visual Studio 2005\Projects\My Application\My Application\bin\Debug\My Application.exe")

            myProcess.StartInfo.WorkingDirectory = "c:\Documents and Settings\User\My Documents\Visual Studio 2005\Projects\My Application\My Application\bin\Debug"

            myProcess.Start()
           
        Else
            MsgBox("My Application.exe file was not found")
        End If

---

Thanks Half,
it works perfect.

One more question.

If I put both applications in the same folder, how to set WorkingDirectory of the second application to Application Directory of the first?

'Application.StartupPath' gives you the path to the dir where the original exe is. Use myProcess.StartInfo.WorkingDirectory = Application.StartupPath

Thanks Half