Can I draw smooth curve in VB?

Can I draw smooth x VS y curve in VB like smooth line curve in Pivot Chart in access? Or, can i use Pivot chart in VB?

What about using the intrinsic 'Circle()' function ? (you can specify an arc length)

can I draw any curve (2d xy curve) using circle? I have two coulmn X and Y in my table which have random values. I want to draw a smooth X Versus Y line curve.

Or: http://vbforums.com/showthread.php?t...light=draw+arc

Ahh, ok ignore (both) those posts :)

How about PSet() ?

You could iterate the x and y values and place a pixel on the screen (or other container).

Thinking that tru, you may end up without lines between the points - probably unwanted.

These may help: http://vbforums.com/search.php?searchid=1442707

if you place the dots close enough together it is a line

here is an example that plots a spiral. originally it was just dots (50 points per circle), but i change it to 5000 and it is a solid line (as far as you and i can see)

vb Code:

Sub extrasub()
Dim col() As Long, r1 As Double, r As Double, px As Double
Dim py As Double, cnt As Long, spir As Long, spirw As Double
Pic1.Cls
px = Pic1.Width / 2
py = Pic1.Height / 2
r = 0 ' diameter of circle to sample 0 to start at center
cnt = 5000  'no of point to sample in circle
spir = 5   ' no of rings in spiral
spirw = (py - r) / spir / cnt
'Text1(0).Move px, py
ReDim col(cnt * spir)
For i = 0 To cnt * spir - 1
        r1 = 360 / cnt * (i) * radians '3.142 / 180
        Pic1.PSet (px + r * Sin(r1), py - r * Cos(r1)), vbRed 'i used this to put a circle i could see for testing
            col(i) = Pic1.Point(px + r * Sin(r1), py - r * Cos(r1))
          r = r + spirw '(py - 1000) / spir / cnt
 
Next
 
End Sub

so you just need to plot enough points on your curve,
or else join the dots together change the code like this

vb Code:

If Not i = 0 Then Pic1.Line (psx, psy)-(px + r * Sin(r1), py - r * Cos(r1)), vbRed
'        Pic1.PSet (px + r * Sin(r1), py - r * Cos(r1)), vbRed 'i used this to put a circle i could see for testing
        '****
        psx = px + r * Sin(r1): psy = py - r * Cos(r1)

declare psx and psy both as double

with 50 points on each circle