winsock - sendData & dataArrival - part 2

I started this thread a while ago in reference to why data sent arrived bunched up. In conclusion, it was because that was the way it was meant to be sent and there were two possible solutions to this. Add a special character at the end of the data and then split the data by that special character when it arrived or use a timer.

I use a combination of these two. I wait 3 seconds before sending data again and use the split to get the data seperated. However, I use the sendData 6 times, which means it takes 18 seconds to send the data. I'm now needing to sendData 10 times. Which means it will make my program take 30 seconds to send its data. That's too long. So I'm thinking of just using the split method. However, is it possible in the following scenario:

So here is my question. I know how to send data with special characters & receive the data and split it at the special characters. I am able to do this because I know how many items are being sent. However, what about when the items you are sending are in a listboxes and the listcount is different everytime? Unless I'm over-thinking, using the special character and splitting is out of the question isn't it? I would have to send the data from each listbox as a seperate sendData using timers to make sure data isn't bunched up. I wouldn't be able to "bunch" all the data together and and try to split it at the receiving end because since the listcount is not the same as before. I can't determine which data came from which listbox.

Anyone get what I'm saying?

No need for any timers or pausing. Just separate each SendData "packet" with a special character at the end and split it up when it arrives.

When sending list data, I usually just separate each list item by a new line (vbCrLf) since chances are, you won't have any new line characters in a list item.

So you would have 3 separaters.

1 is the one you use at the end of your SendData packet.
2nd is the one you use to separate each list item (vbCrLf)
And 3rd is what you use to separate the other info in the packet.

ie:

vb Code:

Dim intLoop As Integer, strPacket As String
 
strPacket = "LIST" & Chr$(2) & "Another part" & Chr$(2) & "Another part" & Chr$(2)
 
For intLoop = 0 To List1.ListCount - 1
    strPacket = strPacket & List1.List(intLoop) & vbCrLf
Next intLoop
 
'Remove last new line if it is there.
If Right$(strPacket, 2) = vbCrLf Then strPacket = Mid$(strPacket, 1, Len(strPacket)-2)
 
strPacket = strPacket & Chr$(4)
 
Winsock.SendData strPacket

So then your data would look like this:

LIST[2]Another part[2]Another part[2]Item1
Item2
Item3
Item4

Where [2] (Chr$(2)) separates each "parameter" or other piece of information in the packet. And [4] (Chr$(4)) separates each actual packet in case they arrive together.

Splitting by [2] (which is Chr$(2)) would give you:

vb Code:

strInfo() = Split(Data, Chr$(2))
'strInfo(0) = LIST
'strInfo(1) = Another part
'strInfo(2) = Another part
'strInfo(3) = Item1
Item2
Item3
Item4

Then splitting strInfo(3) by vbCrLf would give you the list items.

vb Code:

strList() = Split(strInfo(3), vbCrLf)

Then you can loop through the array and add each item to the list.

vb Code:

Dim intLoop As Integer
 
For intLoop = 0 To UBound(strList)
    List1.AddItem strList(intLoop)
Next intLoop
 
Erase strInfo
Erase strList

Thanks for the reply DigiRev. I had a feeling you would be monitoring this forum. ;)

Now please be patient with me because I'm slow when it comes to new things. Also, I'm not 100% sure if this would do what I need. I have more than 1 listbox. Not just one. I can do many listboxes with no problem. The problem is trying to send the data from all the listboxes in 1 shot & splitting it at the receiving end in 1 shot. Well, I can send everything in one shot, just don't know how to split it on the other side to the appropriate listboxes. I don't know if your code does this and I'm just not understanding.

Here is part of the code I use to send the items in the listboxes. Don't pay too much attention to the select case. I just use it for my timer that holds a static integer variable to know what is arriving. I use the @ for the special split character:

vb Code:

Select Case x
    Case 1  'deck cards for u1
        If lstDeckU1.ListCount > 0 Then
            For y = 0 To lstDeckU1.ListCount - 1
                deckCardsU1 = deckCardsU1 & lstDeckU1.List(y) & "@"
            Next y
        Else
            deckCardsU1 = "e@"
        End If
        
        Winsock.SendData deckCardsU1
        
    Case 2  'deck cards for u2
        If lstDeckU2.ListCount > 0 Then
            For y = 0 To lstDeckU2.ListCount - 1
                deckCardsU2 = deckCardsU2 & lstDeckU2.List(y) & "@"
            Next y
        Else
            deckCardsU2 = "e@"
        End If
    
    Winsock.SendData deckCardsU2

Here is part of the code I use to receive & split the items in the listboxes:

vb Code:

Select Case x
            Case 1  'u1 deck
                If unkMsg <> "e@" Then
                    theUpdates = Split(unkMsg, "@")
                    lstDeckU1.Clear
                    For y = 1 To UBound(theUpdates)
                        lstDeckU1.AddItem theUpdates(y)
                    Next y
                End If
                
            Case 2  'u2 deck
                If unkMsg <> "e@" Then
                    theUpdates = Split(unkMsg, "@")
                    lstDeckU2.Clear
                    For y = 1 To UBound(theUpdates)
                        lstDeckU2.AddItem theUpdates(y)
                    Next y
                End If

Before I gave up and resorted to the above code, this is what I had done for the sending part:

vb Code:

Case 1  'deck cards
        If lstDeckU1.ListCount > 0 Then
            For y = 0 To lstDeckU1.ListCount - 1
                deckCards = deckCards & lstDeckU1.List(y) & "@"
            Next y
            deckCards = deckCards & "done@"
        Else
            deckCards = "e@"
        End 
        
        If lstDeckU2.ListCount > 0 Then
            For y = 0 To lstDeckU2.ListCount - 1
                deckCards = deckCards & lstDeckU2.List(y) & "@"
            Next y
            deckCards = deckCards & "done@"
        Else
            deckCards = deckCards & "e@"
        End If

At the receiving part:

vb Code:

Case 1  'decks
 
          theUpdates = Split(unkMsg, "@")
                If theUpdates(1) <> "e" Then                    
                    lstDeckU1.Clear
                    For y = 1 To UBound(theUpdates)
                        If theUpdates(y) <> "done" then
                                lstDeckU1.AddItem theUpdates(y)
                        Else
                                Exit For
                        End If
                    Next y
                End If
                
                z = y + 1
                If theUpdates(z) <> "e" 
                    lstDeckU2.Clear
                    
                    For x = z To UBound(theUpdates)
                       If theUpdates(z) <> "done" then 
                             lstDeckU2.AddItem theUpdates(z)
                       End If
                    Next x
                End If

I think I'm pretty close with the code I wrote but I couldn't finish it. The if/thens & for/nexts got confusing. This code "should" work perfectly for my needs if the listcount for each list had at least 1 item. When the first or both lists are emtpy, which have the string of "e", then I don't know where in the code to insert more code to jump "out" or what code to put period.

Keep in mind I have 6 listboxes. If I'm having trouble with just 2, imagine how much trouble I will have with 6. So I wouldn't mind if I could send the listboxes by 2.

Your problem is that the receiver doesn't know the number of items that belong to a listbox (or whatever). However since your sender knows that number, why don't you send the number of items before you start to send the items. That way the receiver could start the correct for/next loop using just this number!

Damn I remember reading your reply and starting an example project but I must have got sidetracked with my projects.

I'll write an example for you today if I can, if not, then tomorrow. Trying to finish up this chat program. :sick:

I only send data in "Swan plant web" , But I Can't To make Chat online program . T_T . Can You Send Me Simple source Code about The Winsock to Make chat online .

Quote:

---

Originally Posted by GiongTo

I only send data in "Swan plant web" , But I Can't To make Chat online program . T_T . Can You Send Me Simple source Code about The Winsock to Make chat online .

---

Your question doesn't have anything to do with mine. You start a new thread if your reply isn't in reference to what is already started in the thread. However, I see that you're new. Here is a link:

http://www.vbforums.com/showthread.php?t=297308

Sorry, been real busy and I forgot again. But here's an example.

HIHI many Thanks

Ahhhh! vb5 and its lack of vb6 built in functions is annoying. I don't have INSTREV function. However, I'm trying to study your code to see how you went about it. I see you used INSTR to find the "/" during data arrival through calling a function.

I know what INSTR does but what does INSTRREV do again? Does it do the same as INSTR but starts from the right side first?

Don't worry about forgetting & taking a while. I don't have an immediate need for the code. Plus the code I have is working, just not as fast as I would like.

Quote:

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Originally Posted by drivenbywhat

Ahhhh! vb5 and its lack of vb6 built in functions is annoying. I don't have INSTREV function. However, I'm trying to study your code to see how you went about it. I see you used INSTR to find the "/" during data arrival through calling a function.

I know what INSTR does but what does INSTRREV do again? Does it do the same as INSTR but starts from the right side first?

Don't worry about forgetting & taking a while. I don't have an immediate need for the code. Plus the code I have is working, just not as fast as I would like.

---

Yeah, InStrRev is the opposite of InStr, starts from the end of the string, to find the last occurence of something.

I don't think VB5 has Split() either.

I can modify the example to work without these functions. Are these the only 2 that are missing?

INSTRREV & SPLIT are the ones that I know vb5 doesn't have but I'm sure there a few more that I haven't had to use.