Just wondering why 2^8 = 256 and not 512?
can anyone explain that to me lol?
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Just wondering why 2^8 = 256 and not 512?
can anyone explain that to me lol?
2^1 = 2Quote:
Originally Posted by Icyculyr Fr0st
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64
2^7 = 128
2^8 = 256
Hope that helps.
:thumb:
Thanks, but I knew that, but im wondering whyQuote:
2^1 = 2
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64
2^7 = 128
2^8 = 256
2^1 = 2, shouldn't 2^1 = 4? ((2*2)*1) = 4?
just wondering why its 2 and not 4 lol
2x2x2x2x2x2x2x2 = 2^8 = 256
2 = hmm.... = 2^1 = 2
2x2 = 4 = 2^2 = 4
etc.. :confused:
ok, that makes sense, thanks
Just think that ^n is the number of times you have to multiply the same number.Quote:
Originally Posted by Icyculyr Fr0st
For example:
2^0 = 0
Because ^0 is 0 times to multiply 2. In other words.
2*0 = 0
2^1 = 2
Because ^1 is 1 time to multiply 2. In other words.
2*1 = 2
2^2 = 4
Because ^2 is 2 times to multiply 2. In other words.
2*2 = 4
2^3 = 8
Because ^3 is 3 times to multiply 2. In other words.
2*2*2
And so on and so forth.
n0 is 1, not 0.
Oh yeah.Quote:
Originally Posted by penagate
Sorry about that.
Easy way to visualise it:
n0 = 1
n1 = n
n2 = nn
n3 = nnn
n4 = nnnn
nk = nnnnn...[k]
And by the nn he means n*n, just in case someone ever reads this thread and is confused.Quote:
Originally Posted by penagate
Just to add to this:Quote:
Originally Posted by penagate
n-1 = 1 / n
n-2 = 1 / (nn)
n-3 = 1 / (nnn)
n-x = 1 / (nnnnn ... [x])
As pointed by penagate any number (other than zero of course) raised to the power zero has a numerical value of 1 - that is absolutely correct and here is why:Quote:
Originally Posted by tommygrayson
power can be
POSITIVE:
3 ^ 2 = 9
NEGATIVE:
3 ^ -2 = 1/9
ZERO:
3 ^ (2-2) = 9/9 = 1
its also easily visualized with powers of 10 and decimal points.
10^-1 = .10
10^+0 = 1.0
10^+1 = 10.0
It works exactly the same way no matter what base. You just move your decimal.