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How would I find what the lowest possible grade I can recieve on my final exam is (f), given first (i) and second (s) quarter grades using the following equation to find my semester grade...
Final Grade = (1stQuarter * 40%) + (2nd Quarter * 40%) + (Final Exam * 20%)
Any help is much appreciated.
I guess you don't mean "what is the worst possible grade I can get for the semester", as that would simply mean a result of 0 in the final exam.
Assuming that you know what Final Grade is wanted (and what the lowest value is to get that grade), and you want to know the "minimum score" for the final exam to get it, you can simply re-arrange the formula:
Final Grade = (1stQuarter * 40%) + (2nd Quarter * 40%) + (Final Exam * 20%)
=>
Final Grade - ((1stQuarter * 40%) + (2nd Quarter * 40%)) = (Final Exam * 20%)
=>
(Final Exam * 20%) = Final Grade - ((1stQuarter * 40%) + (2nd Quarter * 40%))
=>
Final Exam = (Final Grade - ((1stQuarter * 40%) + (2nd Quarter * 40%))) / 20%
Like this?: 5(g-(i*.4)-(s*.4))=fQuote:
Originally Posted by Frances Farmer
g=final grade
i = first semester grade
s = quater grades
f = exam grade
This is assuming you know what you want to make overall.
Edit: Looks like someone beat me to it.
Sounds to me like you are getting graded pass/fail, so what you want to do is skip the final exam completely, receive a zero score, and still pass the course.
Forget it. Take the final exam and learn something. Taking a test is a learning process. Not taking it is just plain laziness and you learn nothing.