Uploading Image, Naming Problem

I have this upload page, and when it uploads, it just uploads the file, as a file, not a picture, with no extention. Here is my code:

PHP Code:

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if($_POST["action"] == "Upload Image"){
    unset($imagename);
    $memberid = $_SESSION['member_id'];
    if(!isset($_FILES) && isset($HTTP_POST_FILES))
        $_FILES = $HTTP_POST_FILES;
    
    if(!isset($_FILES['image_file']))
        $error["image_file"] = "An image was not found.";
    
    #One Directory for ALL pics, random filename
    $rand1 = rand(1, 99);
    $rand2 = rand(100, 999);
    $rand3 = rand(1000, 9999);
    $rand = $rand3 - $rand2 + $rand1;
    $imagename = $memberid . "_" . $rand;
    
    /*
    #One dir for each member, original file names, or random is file name doesnt exitst
    $imagename = basename($_FILES['image_file']['name']);
    if(empty($imagename))
        $rand1 = rand(1, 99);
        $rand2 = rand(100, 999);
        $rand3 = rand(1000, 9999);
        $rand = $rand3 - $rand2 + $rand1;
        $imagename = $memberid . "_" . $rand;
    */
    
    if(empty($error))
    {
        $newimage = "pics/" . $imagename;
        //$newimage = "pics/$memberid/" . $imagename;
        //echo $newimage;
        $result = @move_uploaded_file($_FILES['image_file']['tmp_name'], $newimage);
        if(empty($result)) {
            $error["result"] = "There was an error moving the uploaded file.";
        } else {
            $url = "http://pics.rapidfriends.com/" . $imagename;
            $sql1 = "SELECT `picture_id` FROM `pictures` WHERE member_id='$memberid'";
            $query1 = mysql_query($sql1);
            $num = mysql_num_rows($query1);
            
            if ($num == "0") {
                $sql2 = "UPDATE `members` SET `default_pic_url`='$url' WHERE member_id='$memberid'";
                $query2 = mysql_query($sql2);
            }
            $caption = $_POST['caption'];
            $sql = "INSERT INTO `pictures` SET url='$url', member_id='$memberid', caption='$caption'";
            $query = mysql_query($sql);
            echo mysql_error();
            echo "Your Picture Was successfuly Uploaded:<br><br>";
            include("includes/functions.php");
            $showimg = getimagesize($url); 
            $imgtag = imageResize($showimg[0], $showimg[1], 150);
            echo "<img src='$url' title='$caption' $imgtag><br><br>Direct URL: $url<br><br><br>";
        }
    }

} 


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in the db, the url is as follows: http://pics.rapidfriends.com/13_6510
notice no extention, and it still goes to a picture, with the jpeg format... I dont understand whats going wrong...

uhh, maybe because you're making the image file's name like this?

PHP Code:

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$imagename = $memberid . "_" . $rand; 
//............
$newimage = "pics/" . $imagename; 


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if YOU don't add the extension, it won't be there. you can use this:

PHP Code:

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$file = $_FILES['image_file']['tmp_name'];
$pos = strrpos($file, '.');
$extension = substr($file, $pos, strlen($file) - $pos);

$imagename .= "{$memberid}_{$rand}{$extension}"; 


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why are there brackets in the string?

curly brackets within a string denote using a variable. this avoids having to break your string or escape something when you don't need to.

PHP Code:

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<?php
  //example 1:
  echo "$this['array']['wont']['print']";
  echo "{$this['array']['will']}";
  
  //example 2:
  $var1 = 'string';
  $var2 = 'text';
  //the following will not print as expected:
  echo "$var1_$var2";
  //PHP will be looking for a variable named either "$var1_" and "$var2", or just one variable named "$var1_text". ("text" comes from adding $var2's actual value onto the variable reference because there is no space)
  //the following will print as expected:
  echo "{$var1}_{$var2}";
?>

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hope that made sense @_@

oh ok. That makes sense thanks!